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Liula [17]
2 years ago
6

The process of removing an electron from a stable nucleus is known as

Chemistry
1 answer:
larisa [96]2 years ago
3 0
The process of removing an electron form a stable nucleus is known as ionization energy. I hope this answered your inquiry, and if you require further assistance feel free to ask.
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What crossed-aldol product results when butanal is heated in the presence of excess benzaldehyde and sodium hydroxide? draw the
alexdok [17]
Answer:
             2-(hydroxy(phenyl)methyl)butanal is formed as cross aldol product.

Explanation:
                   The mild acidic proton present at alpha position in 1-Butanal is abstracted by strong base NaOH. The enolate formed is the conjugate base of 1-Butanal and cacts as a nucleophile. The enolate is then added across carbonyl group of Benzaldeyde and yield 2-(hydroxy(phenyl)methyl)butanal. The reaction is as follow,

8 0
2 years ago
Reaction A has a high activation energy, whereas reacton B has a low activation energy. Which of the statements about reaction A
Alenkinab [10]

Answer:

The correct answer is:

Reaction B is more likely to occur at all than reaction A.

Explanation:

The activation energy in chemistry is the smallest amount of energy required to cause chemical or nuclear reaction in the reactants in chemical or nuclear systems. The activation energy is denoted by E_{a}, and it is measured in Joules (J), KiloJoules (KJ) or Kilocalories per mole (Kcal/mol)

The activation energy can be thought of simply as the minimum amount of energy required to overcome a barrier that prevents a reaction from occurring, hence, from our question, if Reaction A has a high activation energy, it means that the barrier to be overcome before a reaction will occur is large, meaning that the reaction system is more stable and the reaction is less likely to occur than Reaction B which has a low activation energy, meaning that just a relatively small amount of energy, when applied to the reaction system, will initiate a reaction, making it more likely to occur than reaction A.

You should also note that catalysts are substances that are capable of reducing the activation energy of a system, but remains unchanged at the end of the system.

6 0
2 years ago
Given a compound with a mw of 169 amu having 13.60% na, 8.29% n, 35.51% c, 4.77% h, and 37.85% o, determine the number of each a
Arisa [49]
1) Percent composition

<span>Na: 13.60%,
N:     8.29%
C:    35.51%
H:      4.77%
O:   37.85%
     -------------
       100.02%

2) Convert mass percent to molar composition

For that, divide the percent of each element by its atomic mass.

</span>
<span>Na: 13.60 / 22.99 = 0.5916
N:     8.29 / 14.01 = 0.5917
C:    35.51 / 12.01 = 2.9567
H:      4.77 / 1.01 = 4.7228
O:   37.85 / 16.00 = 2.3656

3) Divide each number by the smallest one:

</span>
<span><span>Na:  0.5916 / 0.5916 = 1.0
N:     0.5917 / 0.5916 = 1.0
C:    2.9567 / 0.5916 = 5.0
H:      4.7228 / 0.5916 = 8.0
O:   2.3656</span> / 0.5916 = 4.0

4) State the empirical formula: Na N C5 H8 O4

5) Calculate the mass of the empirical formula:

Multiplicate the number of each atoms times the atomic mass corresponding atomic mass of the atom.

1 * 22.99 + 1 * 14.01 + 5 * 12.01 + 8 * 1.01 + 4 * 16.00 = 169.13

6) Divide the molar mass by the mass of the empirical formula:

169 / 169.13 = 1

7) Conclusion: the molecular formula is Na N C5 H8 O4, so the number of atoms present in the compound formula are:

Na: 1
N: 1
C: 5
N: 8
O: 4
</span>

5 0
2 years ago
Read 2 more answers
Suppose that a certain fortunate person has a net worth of $79.0 billion ($7.90×1010). If her stock has a good year and gains $3
mario62 [17]
A net worth: $79.0 billion.
Value of stock : $3.20 billion.
New net worth:
$79.0 + $3.20 = $82.20 billion = $82.20 * 10^9 = $8.20 * 10^10
7 0
2 years ago
given that the molar mass of Na2SO4 × nH2O is 322.1 g/mol calculate the number of moles of water in this hydrate
Masja [62]
The molar mass of anhydrous Na₂SO₄ = [2(23) + 32 + 4(16)]
                                                                = 142 g/mol

If the molar mass of hydrated Na₂SO₄ = 322 g/mol

Since hydrated salt = Anhydrous Salt + Water

Then the mass of hydration (Water)= 322 g/mol - 142 g/mol    
                                                           = 180 g/mol

Since the molar mass of water itself is 18 g/mol
⇒ Moles of water = 180 g/mol ÷ 18g/mol
                              = 10

Thus n = 10; the formula of the hydrated salt is Na₂SO₄ · 10H₂O (Sodium Sulphate Decahydrate)
7 0
2 years ago
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