Answer:
The required equation is
d = 4c
where d represents the cost of cookies in dollar and c represents the number of boxes of cookies.
Step-by-step explanation:
Given that, the cost of each box of cookies is $4.
It means,
The cost of 1 box of cookies is $4.
The cost of 2 boxes of cookies is $(4+4) =$(2×4)
The cost of 3 boxes of cookies is $(4+4+4) =$(3×4)
The cost of cookies
=(Number of boxes × 4)
The required equation is
d = 4c
where d represents the cost of cookies in dollar and c represents the number of boxes of cookies.
The volume given is 3Pi(x^3) and the radius is x.
The formula for the volume of a cone is V= [1/3]Pi(r^2)*height
=> [1/3]Pi (r^2) x = 3Pi(x^3) =>
(r^2)x = 3*3(x^3) => (r^2)x = 9(x^3) => (r^2) = 9x^2 =>
r = sqrt[9x^2] = 3x.
<span>Answer: r = 3x</span>
First, split the angle into two angles where the values of the six trigonometric functions are known. In this case, π/12 can be split
into π/3−π/4.
cos(π/3−π/4)
Use the difference formula for cosine to simplify the expression. The formula states that cos(A−B)=cos(A)cos(B)+sin(A)sin(B)
cos(π/3)⋅cos(π/4)+sin(π/3)⋅sin(π/4)
The exact value of cos(π/3) is 12, so:
(12)⋅cos(π/4)+sin(π/3)⋅sin(π/4)
The exact value of cos(π/4) is √22.
(12)⋅(√22)+sin(π/3)⋅sin(π/4)
The exact value of sin(π/3) is √32.
(12)⋅(√22)+(√32)⋅sin(π/4)
The exact value of sin(π/4) is √22.
(12)⋅(√22)+(√32)⋅(√22)
Simplify each term:
√24+√64
Combine the numerators over the common denominator.
<span>(√2+√6)
/ 4</span>
Work the information to set inequalities that represent each condition or restriction.
2) Name the
variables.
c: number of color copies
b: number of black-and-white copies
3)
Model each restriction:
i) <span>It
takes 3 minutes to print a color copy and 1 minute to print a
black-and-white copy.
</span><span>
</span><span>
3c + b</span><span>
</span><span>
</span><span>ii) He needs to print
at least 6 copies ⇒
c + b ≥ 6</span><span>
</span><span>
</span><span>iv) And must have
the copies completed in
no more than 12 minutes ⇒</span>
3c + b ≤ 12<span />
4) Additional restrictions are
c ≥ 0, and
b ≥ 0 (i.e.
only positive values for the number of each kind of copies are acceptable)
5) This is how you
graph that:
i) 3c + b ≤ 12: draw the line 3c + b = 12 and shade the region up and to the right of the line.
ii) c + b ≥ 6: draw the line c + b = 6 and shade the region down and to the left of the line.
iii) since c ≥ 0 and b ≥ 0, the region is in the
first quadrant.
iv) The final region is the
intersection of the above mentioned shaded regions.v) You can see such graph in the attached figure.
Answer: The greatest number of plates Lenin can prepare = 4
and there will be 3 chickens and 4 rolls in each plate.
Step-by-step explanation:
Given: Lenin is preparing dinner plates. He has 12 pieces of chicken and 16 rolls.
To make all the plates identical without any food left over, the greatest number of plates Lenin can prepare = G.C.D.(12,16)=4
The number of pieces of chicken in each plate = 
The number of pieces of rolls in each plate = 
So, the greatest number of plates Lenin can prepare = 4
and there will be 3 chickens and 4 rolls in each plate.