The answer is <span>c.CS; US.
In classical conditioning, a new behaviour is learned via association. The stage before conditioning involves: 1. unconditioned stimulus (US) which produces an unconditioned response, and 2. neutral stimulus (NS) which has no effect on a person and produce a response only when paired with </span>unconditioned stimulus. During conditioning, neutral stimulus (NS) and unconditioned stimulus (US) pair and neutral stimulus becomes a conditioned stimulus (CS). In other words, <span>the ns becomes a <u>CS</u> after it reliably signals the impending occurrence of the <u>US</u>. </span>
I believe it's C! (: Oysters!
Good luck, rockstar! I hope all is well, and you pass. (:
The word "cycle" in cell cycle refers to the regular pattern of growth, DNA duplication, and cell division that occurs in eukaryotic cells.
The cell cycle is the term that describes the development and growth of a cell, after its formation and until its reproduction (division into two daughter cells). In eukaryotic cells (cells that include a nucleus) the cell cycle is comprised of two major phases, the interphase and the mitosis. During interphase, the cell grows larger and duplicates its genetic material. During mitosis, the cell divides its genetic material and cytoplasm, creating two daughter cells.
Answer:
1.2 mL
Explanation:
<em>This is a problem of simple dilution. The dilution principle simply agrees that the number of moles before dilution must be equal to the number of moles after dilution.</em>
Recall that: number of moles = mass/molar mass or molarity x volume.
Hence, for the dilution principle:
initial molarity x initial volume = final molarity x final volume.
In this case, initial molarity of NaOH = 1 M, initial volume = ?, final molarity = 0.1 M, final volume = 12.0 mL.
Initial volume = final molarity x final volume/initial molarity
= 0.1 x 12/1 = 1.2 mL
It thus means that 1.2 mL of 1 M NaOH would be taken and then diluted up to 12.0 mL mark by the addition of distilled water in order to produce 12.0 mL, 0.10 M NaOH solution.
