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Jet001 [13]
2 years ago
5

A basketball backboard set that sold for $79 is discounted 15% what is the sale price

Mathematics
2 answers:
Sliva [168]2 years ago
5 0
Just divide 79 dollars to 15.0
mamaluj [8]2 years ago
4 0
You multiply 79 by .85 bc there’s a 15% discount so you want to see what 85% of 79 is.
the answer will be $67.15
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The cost of 5 scarves is $91.25. What is the unit price? The unit price is $ per scarf.
NikAS [45]

Answer:

18.25

Step-by-step explanation:

just divide the total cost of scarves by the number of scarves:

91.25 / 5 = 18.25

6 0
2 years ago
The law of cosines is a2+b2-2abcosC=c2 find the value of 2abcosC
quester [9]
Isolating 2abCos(c) on one side of the equation and using the given values of a, b and c we can find the answer to this question as shown below:

a^{2} + b^{2} -2ab*cos(C)=c^{2}  \\  \\ 
2ab *cos(C)=  a^{2} + b^{2} - c^{2}  \\  \\ 
2ab *cos(C)=2^{2} + 2^{2}- 1^{2} \\  \\ 
2ab*cos(C) = 7
7 0
2 years ago
Read 2 more answers
Below is the five Number summary for a 136 hikers who recently completed the John muir trail JMT the variable is the amount of t
Helga [31]

Answer:

IQR = Q_3 -Q_1 = 28-18 = 10

Now we can find the limits in order to determine outliers like this:

Left = Q_1 -1.5 IQR = 18 -1.5*10=3

Right = Q_1 +1.5 IQR = 18 +1.5*10=33

So for this case the left boundary would be 3, if a value is lower than 3 we consider this observation as an outlier

b. 3

Step-by-step explanation:

For this case we have the following summary:

Minimum = 9 represent the minimum value

Q_1 = 18 represent the first quartile

Median =Q_2= 21 represent the median

Q_3 = 28 represent the third quartil

Maximum=56 represent the maximum

If we use the 1.5 IQR we need to find first the interquartile range defined as:

IQR = Q_3 -Q_1 = 28-18 = 10

Now we can find the limits in order to determine outliers like this:

Left = Q_1 -1.5 IQR = 18 -1.5*10=3

Right = Q_1 +1.5 IQR = 18 +1.5*10=33

So for this case the left boundary would be 3, if a value is lower than 3 we consider this observation as an outlier

b. 3

7 0
2 years ago
An ostrich can run 6 mph faster than a giraffe. An ostrich can run 7 miles in the same time that a giraffe can run 6 miles. Find
LUCKY_DIMON [66]

NOTE THIS IS AN EXAMPLE:

Let t = time, s = ostrich, and g = giraffe.

Here's what we know:

s = g + 5 (an ostrich is 5 mph faster than a giraffe)

st = 7 (in a certain amount of time, an ostrich runs 7 miles)

gt = 6 (in the same time, a giraffe runs 6 miles)

 

We have a value for s, so plug it into the first equation:

(g + 5)t = 7

gt = 6

 

Isolate g so that we can plug that variable value into the equation:

g = 6/t

so that gives us:

(6/t + 5)t = 7

Distribute:

6 + 5t = 7

Subtract 6:

5t = 1

Divide by 5:

t = 1/5 of an hour (or 12 minutes)

 

Now that we have a value for time, we can plug them into our equations:

1/5 g = 6

multiply by 5:

g = 30 mph

 

s = 30 + 5

s = 35 mph

 

Check by imputing into the second equation:

st = 7

35 * 1/5 = 7

7 = 7

5 0
2 years ago
How far should Galileo walk up the inclined plane?
sergejj [24]

Answer:

Step-by-step explanation:

150/x=sin 15

x=150/sin 15 ≈579.56 m

4 0
2 years ago
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