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2 years ago

What is the probability there are exactly 2 customers in line in a two-server model? selected answer:

Mathematics

1 answer:

svlad2 [7]2 years ago

6 0

Im the answer choice is g.

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Rita promises her daughter on her 12th birthday that she will give her $12,000 for college on her 18th birthday. How much does R

almond37 [142]

Answer:

She should invest 6976.74 $ principal on daughter's 12th birthday.

Explanation:

We have I = prt, where I represents simple interest, p represents principal, r represents interest rate, and t represents time in years.

Here p + I = 12,000 $

So, I = 12000-p

Interest rate r = 12% =0.12

Number of years = 18 - 12 = 6 years.

Substituting

12000-p = p x 0.12 x 6

p + 0.72 p = 12000

1.72 p = 12000

p = 6976.74 $

So, she should invest 6976.74 $ principal on daughter's 12th birthday.

6 0

2 years ago

Read 2 more answers

Rory works at a produce packing plant she packed 2172 strawberries last week and put them in a container with 8 strawberries in

mezya [45]

Answer:

Number of containers = 271

Number of strawberries left = 4

Explanation:

Total number of strawberries = 2172.

Number of strawberries per container = 8

Number of strawberry container = Total number of strawberries/Number of strawberries per container.

Number of strawberry container = 2172/8

Refer the figure to see division,

Number of containers = 271

Number of strawberries left = 4

8 0

2 years ago

What is the multiplicative inverse of 5 in z11, z12, and z13? you can do a trial-and-error search using a calculator or a pc?

grin007 [14]

A multiplicative inverse of an integer a is an integer x such that the product ax is congruent to 1 with respect to the modulus m.

1. $Z_{11}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{4};$
$5\cdot 4=20=\overline{9};$
$5\cdot 5=25=\overline{3};$
$5\cdot 6=30=\overline{8};$
$5\cdot 7=35=\overline{2};$
$5\cdot 8=40=\overline{7};$
$5\cdot 9=45=\overline{1};$
$5\cdot 10=50=\overline{6}.$

The multiplicative inverse of 5 in $Z_{11}$ is 9.

2. $Z_{12}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{3};$
$5\cdot 4=20=\overline{8};$
$5\cdot 5=25=\overline{1};$
$5\cdot 6=30=\overline{6};$
$5\cdot 7=35=\overline{11};$
$5\cdot 8=40=\overline{4};$
$5\cdot 9=45=\overline{9};$
$5\cdot 10=50=\overline{2};$
$5\cdot 11=55=\overline{7}.$

The multiplicative inverse of 5 in $Z_{12}$ is 5.

3. $Z_{13}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11},\overline{12}\}.$