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marissa [1.9K]
2 years ago
4

What is the quotient and the remainder for 4911 divided by 23=?

Mathematics
1 answer:
Ede4ka [16]2 years ago
7 0
Hello,


your answer is <span>18x+9xy


Hope this helps</span>
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a 12 foot tall building casts on 8 foot long long shadow. how long of a shadow will a 5 foot tall women have
grin007 [14]
This is just a basic proportion. 5/8 = x/12. So the 5 foot tall women would have a 7.5 foot shadow.
7 0
2 years ago
De acuerdo con los registros de una empresa, se requieren 54 toneladas de naranjas para producir 45 toneladas de concentrado en
worty [1.4K]

Answer:

79.2 tons

Step-by-step explanation:

What must be done is to apply a proportion rule, taking into account what happened in the registry and what is wanted for this new year. In the following way we can calculate the amount of tons of oranges.

Powder concentrate                    Oranges

         45 tons -------------------------> 54 Tons

         66 tons -------------------------> X Tons

X = 66 * 54/45

X = 79.2, that is to say that 79.2 tons are necessary to produce 66 tons of powder concentrate to make juice.

5 0
2 years ago
A nurse is preparing to administer dextrose 5% water (D5W) 250 ml IV to infuse over 2 hr. The nurse should set the IV pump to de
Molodets [167]

Answer:

the answer is 125

Step-by-step explanation:

I divided 250 and 2

125***ANSWER

4 0
2 years ago
Determine if 0.515115111511115111115... is rational or irrational and give
GREYUIT [131]
It’s rational, for a number to be rational you have to be able to write it as a fraction and you can write 0.515115111511115111115... as a fraction.
7 0
2 years ago
General solution of equation sin x + sin 5x = sin 2x + sin 4x is
zaharov [31]

Answer:

x=nπ3, n∈I

Step-by-step explanation:

sin x + sin 5x = sin 2x + sin 4x

⇒⇒   2 sin 3x cos 2x = 2 sin 3x cos x

⇒⇒   2 sin 3x(cos 2x - cos x) = 0

⇒    sin 3x=0 ⇒ 3x=nπ ⇒ x=nπ3⇒    sin 3x=0 ⇒ 3x=nπ ⇒ x=nπ3 , n∈I, n∈I

or    cos 2x−cos x=0 ⇒ cos 2x=cos xcos 2x-cos x=0 ⇒ cos 2x=cos x

⇒   2x=2nπ±x  ⇒  x=2nπ, 2nπ3⇒   2x=2nπ±x  ⇒  x=2nπ, 2nπ3 , n∈I, n∈I

But solutions obtained by x=2nπx=2nπ , n∈I, n∈I or x=2nπ3x=2nπ3 , n∈I, n∈I are all involved in x=nπ3x=nπ3 , n∈I

7 0
2 years ago
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