If Olivia wants to prevent interest capitalization, she must pay the accrued interest each month. That amount is
... I = Prt = $13,100×0.076×(1/12) = $82.97
Over 4 years (48 months), these payments total $82.97×48 = $3982.56.
_____
If no payments are made, the loan balance grows by the multiplier (1 +r/12) each month. Then the amount of interest that will be capitalized at the end of 48 months is ...
... $13,100×((1 +0.076/12)^48 -1) = $4637.01
The difference in these amounts is ...
... $4637.01 -3982.56 = $654.45 . . . . . matches selection a.
I hope this helps you out.
Answer: 
Step-by-step explanation:
The given geometric series are:
a)
on simplifying in decimals, we get
b) 
on simplifying in decimals, we get
c)
on simplifying in decimals, we get
Thus, this geometric series represent 0.4444.
d)
on simplifying in decimals, we get
<span>B. 8.6
Let's substitute the given values into the function and calculate the result. So:
f(t) = Pe^rt
f(t) = 6e^0.06t
f(6) = 6e^(0.06*6)
f(6) = 6e^(0.36)
f(6) = 6*1.433329415
f(6) = 8.599976487
Rounding to the nearest tenth, gives: 8.6
So the answer is "B. 8.6"</span>
Level, x 1 0.8 0.65
time, y 0 1 2
The graph is not a straight line, it is curved. You can observe this only if you include the point (1,0), which is the level at the begining (100%)
The y - intercept is the full level, at the beginning of the experiment.
