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Alla [95]
2 years ago
6

Which table can be created using the equation below? –2 + 4x = y A 2-column table with 3 rows. Column 1 is labeled x with entrie

s negative 5, 0, 3. Column 2 is labeled y with entries negative 22, negative 2, 10. A 2-column table with 3 rows. Column 1 is labeled x with entries negative 22, negative 2, 10. Column 2 is labeled y with entries negative 5, 0, 3. A 2-column table with 3 rows. Column 1 is labeled x with entries negative 5, 0, 3. Column 2 is labeled y with entries negative 18, negative 2, 10. A 2-column table with 3 rows. Column 1 is labeled x with entries negative 18, negative 2, 10. Column 2 is labeled y with entries negative 5, 0, 3.
Mathematics
2 answers:
inessss [21]2 years ago
7 0

Answer:

it is c

Step-by-step explanation:

Pachacha [2.7K]2 years ago
5 0

The correct answer is C. A 2-column table with 3 rows. Column 1 is labeled x with entries negative 5, 0, 3. Column 2 is labeled y with entries negative 18, negative 2, 10.

Explanation:

The purpose of an equation is to show the equivalence between two mathematical expressions. This implies in the equation "–2 + 4x = y" the value of y should always be the same that -2 + 4x. Additionally, if a table is created with different values of x and y the equivalence should always be true. This occurs only in the third option.

   x                 y

   5                -18    

   0                -2

   3                 10

First row:

-2 + 4 (5) = y  (5 is the value of x which is first multyply by 4)

-2 + 20 = -18 (value of y in the table)

Second row:

-2 + 4 (0) y

-2 + 0 = -2

Third row:

-2 + 4 (3) = y

-2 + 12 = 10

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A firm has a revenue function that can be represented by r (x)=700x-0.35x^2, where r (x) is the total revenue (in dollars) and x
Fudgin [204]

Answer:

How many units need to be sold to produce the maximum revenue? 1000 units

How many in dollars is the maximum revenue when the maximum of units are sold? $350,000

Step-by-step explanation:

We get max value of a function if we differentiate it and set it equal to 0.

We need to differentiate r(x) and set it equal to 0 and solve for x.

<u><em>That would be number of units sold to get max revenue.</em></u>

<u><em /></u>

<u>Then we take that "x" value and substitute into r(x) to get the max revenue amount.</u>

<u />

Before differentiating, we see the rules shown below:

f(x)=ax^n\\f'(x)=n*ax^{n-1}

Where

f'(x) is the differentiated function

Now, let's do the process:

r (x)=700x-0.35x^2\\r(x)=700-2*0.35x\\r(x)=700-0.7x\\0=700-0.7x\\0.7x=700\\x=1000

So, 1000 units need to be sold for max revenue

Now, substituting, we get:

r (x)=700x-0.35x^2\\r(1000)=700(1000)-0.35(1000)^2\\r(1000)=350,000

The max revenue amount is $350,000

5 0
2 years ago
If h:k = 2:5, x:y=3:4 and 2h+x:k+2y = 1:2, find the ratio h-x: k-y.​
fenix001 [56]

Given:

h:k=2:5,x:y=3:4,2h+x:k+2y=1:2

To find:

h-x:k-y

Solution:

We have, h:k=2:5 and x:y=3:4.

Let the values of h and k are 2a and 5a respectively.

Let the values of x and y are 3b and 4b respectively.

We have,

2h+x:k+2y=1:2

It can be written as

\dfrac{2h+x}{k+2y}=\dfrac{1}{2}

\dfrac{2(2a)+(3b)}{5a+2(4b)}=\dfrac{1}{2}

\dfrac{4a+3b}{5a+8b}=\dfrac{1}{2}

2(4a+3b)=1(5a+8b)

On further simplification, we get

8a+6b=5a+8b

8a-5a=8b-6b

3a=2b

a=\dfrac{2b}{3}

Now,

h-x:k-y=\dfrac{h-x}{k-y}

h-x:k-y=\dfrac{2-3b}{5a-4b}

h-x:k-y=\dfrac{2\times \dfrac{2b}{3}-3b}{5\times \dfrac{2b}{3}-4b}

h-x:k-y=\dfrac{\dfrac{4b}{3}-3b}{\dfrac{10b}{3}-4b}

On further simplification, we get

h-x:k-y=\dfrac{\dfrac{4b-9b}{3}}{\dfrac{10b-12b}{3}}

h-x:k-y=\dfrac{-5b}{-2b}

h-x:k-y=\dfrac{5}{2}

h-x:k-y=5:2

Therefore, the ratio h-x:k-y is 5:2.

8 0
1 year ago
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