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RideAnS [48]
2 years ago
7

When the alcohol thermometer is placed in 20∘c water, what temperature will the thermometer record?

Chemistry
2 answers:
katovenus [111]2 years ago
7 0

When an alcohol thermometer is placed in 20{\text{ }}^\circ {\text{C}} water, the thermometer will record temperature \boxed{{\text{greater than }}20{\text{ }}^\circ {\text{C}}}.

Further explanation:

Temperature:

It is a physical quantity that measures the hotness or coldness of any substance. It is an intensive property. The device used to measure temperature is a thermometer. Three common scales are there to measure the temperature of a substance. These are the Celsius scale, Kelvin scale, and Fahrenheit scale. SI unit of temperature is Kelvin (K).

An alcohol thermometer is a substitute for mercury thermometers. It is an equipment that is used to measure the temperature of any object. The alcohol thermometer has less toxic contents as compared to those present in mercury thermometer.

Thermal expansion arises when there is change in the size and shape of the substance with a change in temperature.

Volume expansion occurs when a substance is expanded in three-dimensional space. The expression for volume expansion is as follows:

\Delta V = {V_0}\beta \Delta T         …… (1)                                      

Here,

\Delta V is the change in volume.

{V_0} is the initial volume.

\beta is the coefficient of volume expansion.

\Delta T is the temperature change.

Rearrange equation (1) for \Delta T.

 \Delta T =\dfrac{{\Delta V}}{{{V_0}\beta }}   …… (2)                                            

The change in temperature is inversely related to the coefficient of volume expansion. The value of \beta for mercury is 1.82\times10^{-4}\ \ ^{\circ}\text{C}^{-1} and that for alcohol is 1.12 \times {10^{ - 4}}{\text{ }}^\circ {{\text{C}}^{ - 1}}. So the temperature recorded by the alcohol thermometer will be greater than 20{\text{ }}^\circ {\text{C}}.

Learn more:

1. Which of these is an extensive property? brainly.com/question/1398514

2. Which of the phase changes is an exothermic change? brainly.com/question/1875234

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Thermodynamics

Keywords: temperature, alcohol thermometer, hotness, coldness, intensive, extensive, thermal expansion, volume expansion.

Svet_ta [14]2 years ago
5 0
The thermometer operates under the concept of the Zeroth Law of Thermodynamics. The thermometer displays the temperature of its surroundings, regardless of the identity of the substance. So, if the water is 20°C, then the thermometer displays 20°C.
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2 years ago
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5. A Dumas bulb is filled with chlorine gas at the ambient pressure and is found to contain 7.1 g of chlorine when the temperatu
kati45 [8]

Answer:

a. The original temperature of the gas is 2743K.

b. 20atm.

Explanation:

a. As a result of the gas laws, you can know that the temperature is inversely proportional to moles of a gas when pressure and volume remains constant. The equation could be:

T₁n₁ = T₂n₂

<em>Where T is absolute temperature and n amount of gas at 1, initial state and 2, final states.</em>

<em />

<em>Replacing with values of the problem:</em>

T₁n₁ = T₂n₂

X*7.1g = (X+300)*6.4g

7.1X = 6.4X + 1920

0.7X = 1920

X = 2743K

<h3>The original temperature of the gas is 2743K</h3><h3 />

b. Using general gas law:

PV = nRT

<em>Where P is pressure (Our unknown)</em>

<em>V is volume = 2.24L</em>

<em>n are moles of gas (7.1g / 35.45g/mol = 0.20 moles)</em>

R is gas constant = 0.082atmL/molK

And T is absolute temperature (2743K)

P*2.24L = 0.20mol*0.082atmL/molK*2743K

<h3>P = 20atm</h3>

<em />

7 0
2 years ago
Suppose total world energy consumption of fossil fuels, equal to 3×1017 kJ/yr, were to be obtained entirely by combustion of pet
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Explanation:

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thx for the challenge !

3 0
2 years ago
The solubility of N2 in blood can be a serious problem (the "bends") for divers breathing compressed air (78% N2 by volume) at d
OLga [1]

Answer:

The volume is 19.7 mL

Explanation:

<u>Step 1</u>: Given data

Pressure at sea level = 1.00 atm

Pressure at 50 ft = 2.47535 atm

kH for N2 in water at 25°C is 7.0 × 10−4 mol/L·atm

Molarity (M) = kH x P

<u>Step 2</u>: Calculate molarity

M at sea level:

M = 7.0*10^-4 * (1.00atm * 0.78) = 5.46*10^-4 mol/L

M at 50ft:

M = 7.0*10^-4 * (2.47535atm * 0.78) = 13.5*10^-4 mol/L

We should find the volume of N2. To find the volume whe have to find the number of moles first. This we calculate by calculating the difference between M at 50 ft and M at sea level.

13.5*10^-4 mol/L - 5.46*10^-4 mol/L = 8.04*10^-4 mol/L

Step 3: Calculate volume

P*V=nRT

with P = 1.00 atm

with V = TO BE DETERMINED

with n =  8.04*10^-4 mol/L  *1L = 8.04*10^-4

with R= 0.0821 atm * L/ mol *K

with T = 25 °C = 273+25 = 298 Kelvin

To find the volume, we re-organize the formula to: V=nRT/P

V= (8.04*10^-4 mol * 0.0821 (atm*L)/(mol*K)* 298K ) / 1.00atm = 0.0197L = 19.7ml

The volume is 19.7 mL

5 0
2 years ago
A 250. ml sample of 0.0328m hcl is partially neutralized by the addition of 100. ml of 0.0245m naoh. find the concentration of h
Ksenya-84 [330]

Answer: 0.0164 molar concentration of hydrochloric acid in the resulting solution.

Explanation:

1) Molarity of 0.250 L HCl solution : 0.0328 M

Molarity=\frac{\text{Number of moles}}{\text{Volume of solution in liters}}=0.0328=\frac{\text{Number of moles}}{0.250 L}

Moles of HCl in 0.250 L solution = 0.0082 moles

2) Molarity of 0.100 L NaOH solution : 0.0245 M

Molarity=\frac{\text{Number of moles}}{\text{Volume of solution in liters}}=0.0245=\frac{\text{Number of moles}}{0.100 L}

Moles of NaOH in 0.100 L solution = 0.00245 moles

3) Concentration of hydrochloric acid in the resulting solution.

0.00245 moles of NaOH will neutralize 0.00245 moles of HCl out of 0.0082 moles of HCl.

Now the new volume of the solution = 0.100 L +0.250 L = 0.350 L

Moles of HCl left un-neutralized = 0.0082 moles - 0.00245 moles =  0.00575 moles

Molarity=\frac{\text{number of moles}}{\text{volume of solution in L}}

Molarity of HCl left un-neutralized :\frac{0.00575 moles}{0.350L}=0.0164 M

0.0164 molar concentration of hydrochloric acid in the resulting solution.

3 0
2 years ago
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