Answer:
52 tickets cost $10 and 18 tickets cost $12
Step-by-step explanation:
10x+12y=804. (1)
x+y=70. (2)
From (2)
x=70-y
Substitute x=70-y into (1)
10x+12y=804
10(70-y)+12y=804
700-10y+12y=804
700+2y=804
2y=804-700
2y=104
y=104/2
y=52
Recall
x+y=70
x+52=70
x=70-52
x=18
52 tickets cost $10 and 18 tickets cost $12
Answer:
A Type II error is when the null hypothesis is failed to be rejected even when the alternative hypothesis is true.
In this case, it would represent that the new program really increases the pass rate, but the sample taken is not enough statistical evidence to prove it. Then, the null hypothesis is not rejected.
The consequence is that the new method would be discarded (or changed) eventhough it is a real improvement.
Step-by-step explanation:
Answer:
The required inequality is
.
Step-by-step explanation:
The given inequalities are


where, x is the driver's age (in years), A(x) is driver’s reaction time to audio stimuli and V(x) is his or her reaction time to visual stimuli, 16 ≤ x ≤ 70.
We need to find an inequality that can be use to find the x-values for which A(x) is less than V(x).



Combine like terms.

where, 16 ≤ x ≤ 70.
Therefore, the required inequality is
.
Graph B represents the function g(x)=x^3-2 Graph C represents the function h(x)=2x^3
Answer:
II case.
Step-by-step explanation:
Given that a catering company prepared and served 300 meals at an anniversary celebration last week using eight workers.
The week before, six workers prepared and served 240 meals at a wedding reception.
Productivity is normally measured by number of outputs/number of inputs
Here we can measure productivity as
no of meals served/no of workers
In the I case productivity =
In the II case productivity = 
Obviously II case productivity is more as per worker 40 meals were served which is more than 37.5 meals per worker in the I case.