Which expression is equivalent to 59.06?

Which expression is equivalent to RootIndex 4 StartRoot x Superscript 10 Baseline EndRoot?

Darya [45]

Answer:

Which expression is equal to ? The correct answer is B.

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8 0

2 years ago

A convenience store has two separate locations where customers can be checked out as they leave. These locations each have two c

OverLord2011 [107]

Answer:

E(X) = 1.28

Var(X) = 0.6016

E(X | Y=2) = 1.6667

Var(X | Y=2) = 0.4272

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Use operations of decimal, fraction, and percent numbers and your models from Part (b) to solve the following application proble

KIM [24]

2. $5.10
4. 18%
I don't feel like doing 5 right now I'm watching hulu haha

4 0

2 years ago

A manufacturing company produces valves in various sizes and shapes. One particular valve plate is supposed to have a tensile st

maxonik [38]

Answer:

$z=\frac{5.0611-5}{\frac{0.2803}{\sqrt{42}}}=1.413$

$p_v =2*P(z>1.413)=0.158$

If we compare the p value and the significance level given $\alpha=0.1$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the average tensile strength is different from 5lbs/mm at 10% of signficance

Step-by-step explanation:

Data given and notation

$\bar X=5.0611$ represent the sample mean

$\sigma=0.2803$ represent the population standard deviation for the sample

$n=42$ sample size

$\mu_o =5$ represent the value that we want to test

$\alpha=0.1$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean is different from 5, the system of hypothesis would be:

Null hypothesis: $\mu = 5$

Alternative hypothesis: $\mu \neq 5$

If we analyze the size for the sample is > 30 but and we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{5.0611-5}{\frac{0.2803}{\sqrt{42}}}=1.413$

P-value

Since is a two sided test the p value would be:

$p_v =2*P(z>1.413)=0.158$

Conclusion

If we compare the p value and the significance level given $\alpha=0.1$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the average tensile strength is different from 5lbs/mm at 10% of signficance

8 0

2 years ago

Ben luna received his bank statement with a $27.04 fee for a bounced check. he has an $815.75 monthly mortgage payment paid thro

morpeh [17]

Answer:

Step-by-step explanation:

Ben's checkbook balance : $1,395.28 Bank's balance: $119.17

Credited (add) credited (add)

Interest : $1.23 Deposit :$530.50

$1,396.51 $649.67

Debited (deduct) Debited (deduct)

fee for bounced check : $27.04 Outstanding checks

Monthly mortgage : $815.75 Check No 234: $80.30

teller fee : $3.00 Check No 235: $28.55

check printing fee : $3.00

ATM card fee : $6.40

$855.19 $108.85

Balance : $541.32 $540.82

Reconcile balance of check book and bank statement.

4 0

2 years ago