Question

A bobsleigh with four people on board has a total mass of 610 kg. How fast is the sleigh moving if it has a kinetic energy of 40.0 kJ?

Answer 1

40 kj to j is 40000 j, we know that KE=(1/2)mv², therefore v=√2K/m, therefore v=√2×40000j/610kg, v=11.5 m/s

Answer 2

Answer:

v= 11.45 $\frac{m}{s}$

Explanation:

kinetic equation

$E_{k} = \frac{1}{2} * m * v^{2}$, $E_{k} = 40.0 k J$ , $m=610 kg$

$E_{k}*2 = m * v^{2}\\\frac{2*E_{k}}{m} = v^{2} \\v = \sqrt{\frac{2*E_{k}}{m} } \\v = \sqrt{\frac{2*40x10^{3} \frac{kg*m^{2} }{s^{2}} }{610 kg} } = \sqrt{131.147 \frac{m^{2}}{s^{2}} }$

$v= 11.45 \frac{m}{s}$