It is advisable to wear long sleeve when when a student is working in a chemistry lab so that to protect arms from lab chemicals. when someone enter the chemistry lab to wort or to study should be well prepared with appropriate gears and security measure to avoid injury.
Answer : The role of limiting reagent or reactant is important in a chemical reaction because it can help the chemist to predict that complete amount of reactant is consumed, as it is limiting the reaction, only required moles of products can get formed instead of the theoretical yield where the perfect amount is used.
In short, Limiting reactant in a chemical reaction is the substance that is totally consumed when the chemical reaction is found to be complete.
Answer:
The answer to your question is V2 = 825.5 ml
Explanation:
Data
Volume 1 = 750 ml
Temperature 1 = 25°C
Volume 2= ?
Temperature 2 = 55°C
Process
Use the Charles' law to solve this problem
V1/T1 = V2/T2
-Solve for V2
V2 = V1T2 / T1
-Convert temperature to °K
T1 = 25 + 273 = 298°K
T2 = 55 + 273 = 328°K
-Substitution
V2 = (750 x 328) / 298
-Simplification
V2 = 246000 / 298
-Result
V2 = 825.5 ml
A gaseous compound is 30.4% nitrogen and 69.6% oxygen by mass. A 5.25-g sample of the gas occupies a volume of 1.00 L and exerts a pressure of 1.26 atm at -4.0°C. Which of the following is its molecular formula?
1) NO2
2) N3O6
3) N2O5
4) N2O4
5) NO
<span>When two electrical charges, of
opposite sign and equal magnitude, are separated by a distance, a dipole is
established. The size of a dipole is measured by its dipole moment (</span>μμ). Dipole moment is measured in Debye
units, which is equal to the distance between the charges multiplied by the
charge (1 Debye equals 3.34×10−30Cm3.34×10−30Cm). The dipole moment
of a molecule can be calculated by Equation 1.11.1:
μ = qr
where
<span>
<span>μ⃗ μ→ is the dipole moment vector</span>
<span>qiqi is the magnitude of the ithith charge, and</span>
<span>r⃗ ir→i is the vector representing the position
of ithith charge.</span>
</span>
r = μ/q
<span>r = [0.838D(3.34×10−30 C⋅m/ 1D)]/ (1.6×10−19
C) *0.124
</span>
r = 1.41 x10^-10 m
