Answer:
The answer is This should be possible in O(m+n) with BFS.
Explanation:
Give us a chance to take your chart G. Complete a BFS on the diagram. Check every one of the hubs in the diagrams as visited as normal with BFS. Rather than adding only hubs to the line in the DFS include hubs in addition to number of incoming ways. On the off chance that a hub that has been visited ought to be included disregard it. On the off chance that you discover a hub again which is as of now present in your line don't include it once more, rather include the checks together. Proliferate the depends on the line while including new hubs when you experience the last hub i.e the goal hub the number that is put away with it is the quantity of briefest ways in the diagram.
Answer:
$3,900
Explanation:
A speed boat bought for $13,000 depreciates at 10% per annum compounded continuously. What is its value after 7 years?
Round the answer to nearest dollar.
Amount of depreciation per annum = 13,000 x 10% = $1,300
Amount of depreciation in 7 years = 1,300 x 7 = $9,100
Value of Speed boat after 7 years = 13,000 - 9,100 = $3,900
Answer:
B) 3 scarves
Explanation:
total fixed costs per day = $60 (rent)
selling price per scarf = $40
variable cost per scarf = $15
contribution margin = selling price per unit - variable cost per unit = $40 - $15 = $25
break even formula in units = total fixed costs / contribution margin = $60 / $25 = 2.4 units, since you can only sell complete units, the break even amount is 3 scarves.
Answer:
Explanation:
the solution is shown in the picture attached below
