This is late, but for anyone searching the answer up in the future, the answer on Edg.enuity is the last one - where the graph starts out as a horizontal line, then decreases and touches the x-axis, then increases again.
Good luck on your assignment !!
Answer:
27 hours
Step-by-step explanation:
The regular hours are paid normally, 21/hr hence working for 40 hours, Michael earns 40*21=$840
To work x hours paid overtime as 1.5 of the normal rate, the rate would be $21*1.5=$31.5/hr
X hours multiplied by rate of $31.5/hr should be at least equal to $840
31.5x>=840
X>=840/31.5>=26.6667 hours and when rounded off
X is 27 hours
Answer:
The probability that the pirate misses the captain's ship but the captain hits = 0.514
Step-by-step explanation:
Let A be the event that the captain hits the pirate ship
The probability of the captain hitting the pirate ship, P(A) = 3/5
Let B be the event that the pirate hits the captain's ship
The probability of the pirate hitting the captain's ship P(B) = 1/7
The probability of the pirate missing the captain's ship, P'(B) = 1 - P(B)
P'(B) = 1 - 1/7 = 6/7
The probability that the pirate misses the captain's ship but the captain hits = P(A) * P(B) = 3/5 * 6/7
= 0.514
Answer:
A) b) and c) answer has been explained below.
Step-by-step explanation:
For the question would use 1's and 0's and taking probabilities to be equal for both using random test pattern whose formula is when p = q
then Simplify to
P[k] = nCk /2^n
A.Probability that all bits are 1s
16c16/2^16 = 1/65536
B. Probability that all bits are 0s
16c0/2^16 = 1/65536
C.the probability that exactly 8 bits are 1s and 8 bits are 0s
16c8/2^16 = 12870/65536 =>0.1963 ≈ 19.63%
As usual, draw a diagram. You can easily see that if you are x away from the wall,
<span>the angle of elevation of the bottom of the screen (A) is </span>
<span>cotA = x/3 </span>
<span>A = arccot(x/3) </span>
<span>angle B to the top is </span>
<span>cotB = x/10 </span>
<span>B = arccot(x/10) </span>
<span>So, since θ = B-A </span>
<span>dθ/dt = dB/dt - dA/dt </span>
<span>= -3/(x^2+9) + 10/(x^2+100) </span>
<span>= 7(x^2-30)/((x^2+9)(x^2+100)) </span>
<span>so, at x=30 </span>
<span>dθ/dt = 203/30300</span>
