answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nostrana [21]
2 years ago
4

A wooden raft has a mass of 50 kg. when empty it floats in water (density 1000 kg/m3) with 69% of its volume submerged. what mas

s of sand can be put on the raft without it sinking?
Physics
1 answer:
anyanavicka [17]2 years ago
8 0
First we find the volume of the boat.  

m*g*0.69V = 50*g 

 V = 50/(.69 * 1000) =0.072 m^-3 

 For the boat to be fully submerged the maximum buoyant force (p*g*V) must equal the total weight of boat & sand   

 p*g*V = (m + 50)*g   

 m = p*V - 50 = 1000*0.072 - 50 = 22 

 22 kg is the maximum amount of sand that can be put on before the boat sinks.
You might be interested in
To fully describe the photoelectric effect, scientists must consider which of
erastovalidia [21]

Answer:

D. Light only

Explanation:

This is because photoelectric effect is a phenomenon in which electrically charged particles are emitted from a material when light is incident on it.

The light generates the energy which causes the material to emit electrons.

These electrons are only emitted at certain values of light energy, this thus shows that the light has to be quantized since electrons are not emitted over a range of values of light energy.

Thus, to fully describe the photoelectric effect, only light needs to be quantized.

8 0
2 years ago
A block weighing 400 kg rests on a horizontal surface and supports on top of it ,another block of weight 100 kg which is attache
Paladinen [302]

Answer:

F_a=1470\ N

Explanation:

<u>Friction Force</u>

When objects are in contact with other objects or rough surfaces, the friction forces appear when we try to move them with respect to each other. The friction forces always have a direction opposite to the intended motion, i.e. if the object is pushed to the right, the friction force is exerted to the left.

There are two blocks, one of 400 kg on a horizontal surface and other of 100 kg on top of it tied to a vertical wall by a string. If we try to push the first block, it will not move freely, because two friction forces appear: one exerted by the surface and the other exerted by the contact between both blocks. Let's call them Fr1 and Fr2 respectively. The block 2 is attached to the wall by a string, so it won't simply move with the block 1.  

Please find the free body diagrams in the figure provided below.

The equilibrium condition for the mass 1 is

\displaystyle F_a-F_{r1}-F_{r2}=m.a=0

The mass m1 is being pushed by the force Fa so that slipping with the mass m2 barely occurs, thus the system is not moving, and a=0. Solving for Fa

\displaystyle F_a=F_{r1}+F_{r2}.....[1]

The mass 2 is tried to be pushed to the right by the friction force Fr2 between them, but the string keeps it fixed in position with the tension T. The equation in the horizontal axis is

\displaystyle F_{r2}-T=0

The friction forces are computed by

\displaystyle F_{r2}=\mu \ N_2=\mu\ m_2\ g

\displaystyle F_{r1}=\mu \ N_1=\mu(m_1+m_2)g

Recall N1 is the reaction of the surface on mass m1 which holds a total mass of m1+m2.

Replacing in [1]

\displaystyle F_{a}=\mu \ m_2\ g\ +\mu(m_1+m_2)g

Simplifying

\displaystyle F_{a}=\mu \ g(m_1+2\ m_2)

Plugging in the values

\displaystyle F_{a}=0.25(9.8)[400+2(100)]

\boxed{F_a=1470\ N}

8 0
2 years ago
The following times are given using metric prefixes on the base SI unit of time: the second. Rewrite them in scientific notation
Leno4ka [110]

Answer: a=9.8*10^-10s

b=9.8*10^-13s

c=1.7*10^-8s

d=5.57*10^-4s

Explanation:

a) given 980 ps

Expected answer is 980 * 10^-12

Therefore, 980ps = 9.8*10^-10s

b) given 980 fs

Expected answer is 980 * 10^-15

Therefore, 980fs = 9.8*10^-13s

c) given 17 ns

Expected answer is 17 * 10^-9

Therefore, 17ns = 1.7*10^-8s

d) given 577 μs

Expected answer is 577 * 10^-6

Therefore, 577μs = 5.57*10^-4s

a=9.8*10^-10s

b=9.8*10^-13s

c=1.7*10^-8s

d=5.57*10^-4s

8 0
2 years ago
Read 2 more answers
A skydiver is using wind to land on a target that is 50 m away horizontally. The skydiver starts from a height of 70 m and is fa
elena55 [62]

Answer:

Answer:

15.67 seconds

Explanation:

Using first equation of Motion

Final Velocity= Initial Velocity + (Acceleration * Time)  

v= u + at

v=3

u=50

a= - 4 (negative acceleration or deceleration)  

3= 50 +( -4 * t)

-47/-4 = t

Time = 15.67 seconds

6 0
2 years ago
A cart moves along a track at a velocity of 3.5 cm/s. when a force is applied to the cart, its velocity increases to 8.2 cm/s. i
oksian1 [2.3K]
Acceleration, in physics, is the rate of change of velocity of an object with respect to time. <span> Anytime an object's velocity is changing, the object is said to be </span><span>accelerating. It can be calculated as follows:

acceleration = 8.2 - 3.5 / 1.5 = 3.1 m/s</span>²

Hope this answers the question.
5 0
2 years ago
Read 2 more answers
Other questions:
  • How much heat must be absorbed by 375 grams of water to raise its temperature by 25°c
    8·2 answers
  • An electron is pushed into an electric field where it acquires a 1-v electrical potential. suppose instead that two electrons ar
    5·2 answers
  • A clock has radius of 0.5m. The outermost point on its minute hand travels along the edge. What is its tangential speed?
    11·1 answer
  • two coconuts fall freely from rest at the same time, one twice as high as the other. If The coconut from the shorter tree takes
    8·1 answer
  • A ship sailing in the Gulf Stream is heading 25.0º west of north at a speed of 4.00 m/s relative to the water. Its velocity rela
    11·1 answer
  • An ore sample weighs 17.50 N in air. When the sample is suspended by a light cord and totally immersed in water, the tension in
    13·1 answer
  • Charge of uniform density (40 pC/m^2) is distributed on a spherical surface (radius = 1.0 cm), and a second concentric spherical
    14·1 answer
  • You are riding a rollercoaster going around a vertical loop, on the inside of the loop. If the loop has a radius of 30 meters, h
    14·2 answers
  • A baton twirler has a baton of length 0.36 m with masses of 0.48 kg at each end. Assume the rod itself is massless. The rod is f
    15·1 answer
  • How long will it take a 2190 W motor to lift a 1.47 x 104 g box, 6.34 x 104 mm vertically.​
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!