How much heat must be absorbed by 375 grams of water to raise its temperature by 25°c

2 answers:

7 0

<span>the formula q = 375 g * 25 C * 4.186 J / (g*C) = 39,243.75 J q represents the heat in Joules , m the mass in grams, difference of temperature in Celsius degree, and 4.186 J/(g*C) is the specific heat of water( I assume the water is in liquid from and will remain liquid). Approximately 39.24 kJ once you round and transform to kJ..1 kJ=1000J</span>

N76 [4]2 years ago

4 0

Answer:

Explanation:

From H= mc×temp rise

m= mass of water = 375g or 0.375kg

c= heat capacity of water = 4200JKg-1

H= 0.375×4200×25=39375J or 39.375KJ

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