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2 years ago

How much heat must be absorbed by 375 grams of water to raise its temperature by 25°c

2 answers:

7 0

the formula q = 375 g * 25 C * 4.186 J / (g*C) = 39,243.75 J q represents the heat in Joules , m the mass in grams, difference of temperature in Celsius degree, and 4.186 J/(g*C) is the specific heat of water( I assume the water is in liquid from and will remain liquid). Approximately 39.24 kJ once you round and transform to kJ..1 kJ=1000J

N76 [4]2 years ago

4 0

Answer:

Explanation:

From H= mc×temp rise

m= mass of water = 375g or 0.375kg

c= heat capacity of water = 4200JKg-1

H= 0.375×4200×25=39375J or 39.375KJ

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irina1246 [14]

As a sound source gets closer, both the volume and the pitch of the sound increased. Then, as the sound source passed by you, both the volume and the pitch of the sound decreased.
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2 years ago

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To prevent collisions and violations at intersections that have traffic signals, use the _____ to ensure the intersection is cle

Ann [662]

The answer should be:
To prevent collisions and violations at intersections that have traffic signals, use the delayed acceleration technique to ensure the intersection is clear before you enter it.
Delayed acceleration technique refers to waiting to go through an intersection until you have a chance to scan for other vehicles.

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2 years ago

In this problem, you will analyze a system composed of two blocks, 1 and 2, of respective masses m1 and m2. To simplify the anal

Dafna1 [17]

Answer:

a) p = m1 v1 + m2 v2 , b) dp / dt = m1 a1 + m2 a2 , c) It is equivalent to force

dp / dt = 0

Explanation:

In this problem we have two blocks and the system is formed by the two bodies.

Part A. Initially they ask us to find the moment of the whole system

p = m1 v1 + m2 v2

Part B.

Find the derivative

dp / dt = m1 dv1dt + m2 dv2 / dt

dp / dt = m1 a1 + m2 a2

Part C.

Let's analyze the dimensions

m a = [kg] [m / s2] = [N]

It is equivalent to force

Part d

Acceleration is due to a net force applied

Part e

The acceleration of block 1 is due to the force exerted by block 2 during the moment change

Part f

Force of block 1 on block 2

True f12 = m1a1 f21 = m2a2

Part g

By the law of action and reaction are equal magnitude F12 = f21

Part H

dp / dt = 0

Isolated system F12 = F21 and the masses are constant. The total moment is only redistributed

7 0

2 years ago

A newly discovered planet is found to have density 2/3 Pe and radius 2Re, where Pe and Re are the density and radius of the Eart

Leviafan [203]

Answer: D. 13 N/kg

Explanation:

The surface gravitational field is given by acceleration due to gravity on the planet (g). Let the value of it on a newly discovered planet be g'.

$g = G\frac{M_e}{R_e ^2}=9.81 N/kg\\ g'=G\frac{M_p}{R_p ^2}$

We know that the mass is given by product of volume and density. So,

$M_e = \rho_e \times \frac{4}{3} \pi R_e^3\\ M_p= \rho_p \times \frac{4}{3} \pi R_p^3$

It is given that,

$\rho_p = \frac{2}{3}\rho_e$

$R_p = 2 R_e$

$\Rightarrow M_p=\frac{2}{3}\rho_e \times \frac{4}{3} \pi (2R_e)^3= \frac{16}{3} M_e$

$g'=G\frac{16M_e}{3\times (2R_e)^2}=\frac{4}{3}\times G\frac{M_e}{R_e ^2}=\frac{4}{3}g = 13 N/kg$

4 0

2 years ago

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Magnus has reached the finals of a strength competition. In the first round, he has to pull a city bus as far as he can. One end

iragen [17]

Answer:

The workdone is $W_d =-4400J$

Explanation:

The free body diagram is shown on the first uploaded image

From the question we are given that

The force is on the force gauge $F = 2750 N$

The distance that Magnus pulled the bus $d = 1.60m$

Generally the workdone by the tension force on Magnus is

$Workdone = Force * displacement \ in \ the \ direction \ of \ force$

$W_d = F * (-d)$

This negative sign show that is tension force is in the opposite direction to Magnus movement (i.e the movement of the bus )

Substituting value we have

$Workdone = - 2750 * 1.60$

$=-4400 J$

7 0

2 years ago