(4*4*10)*3
160*3=480
(5*3*10)*2
150*2=300
480+300=780 cub. meters
Μ = 500, population mean
σ = 110, population stadard deviation
The given table is
z 0.00 0.25 0.35 0.45 1.00 1.26 1.35 1.36
P 0.5000 0.5987 0.6368 0.6736 0.8413 0.8961 0.9115 0.9131
Range of random variable is X = [350, 550].
Calculate z-score for x = 350.
z = (350 - 500)/110 = -1.364
From the given tables,
The probability at x = 350 is
1 - 9131 = 0.0869
Calculate the z-score for x = 550.
z = (550 - 500)/110 = 0.454
From the given tables,
The probability at x = 550 is 0.6736
The probability that x =[350,550] is
0.6736 - 0.0869 = 0.5867
Answer: 0.5867 (or 58.7%)
Answer:
After 5 hours, the number of bacteria will be 1024
Step-by-step explanation:
1 times 4 = 4
4 times 4 = 16
16 times 4 = 64
64 times 4 = 256
256 times 4 = 1024
It will take around 5 hours to exceed 1000
Answer:
- Emma made a mistake. The slope should be -40.
Step-by-step explanation:
<u>Pair of points (x, y):</u>
- (165, 900) and (180, 300)
<u>Slope formula:</u>
<u>Calculate the slope:</u>
- Slope = (300 - 900)/(180 - 165) = -600/15 = -40
Answer:
$163.54
Step-by-step explanation:
Volume of rectangular container = 10m^3
Length = 2(width)
Material for the base cost $10 per square meter
Material for the side cost $6 per square meter
Volume = L*B*H
L= 2W
V = (2W).W. H
10 = 2W^2.H
H = 10 /2W^2
H = 5/W^2
Let C(w) = cost function
C(w) = 10(L.W) + 6(2.L.H + 2.W.H)
= 10(2W.W) + 6(2.2W.H + 2.W.H)
= 10(2W^2) + 6(4W.H + 2.W.H)
= 10(2W^2) + 6(4W*5/W^2 + 2.W*5/W^2)
= 20W^2 + 6(20/W + 10/W)
= 20W^2 + 6((10+20)/W)
= 20W^2 + 6(30/W)
C(w) = 20W^2 + 180/W
To find the minimum value, differentiate C with respect to w
C'(w) = 40W - 180/W^2
Put C'(w) = 0
0 = 40W - 180/W^2
40W = 180/W^2
40W^3 = 180
W^3 = 180/40
W^3 = 4.5
W = cube rt(4.5)
W = 1.65m
C = 20(1.65)^2 + 180/1.65
C = 54.45 + 109.09
C= $163.54
Minimum cost = $163.54
