Answer:
m = - 5
Step-by-step Explanation:
Ray Cupple bought a basic car costing $26,500.00, with options costing $725.00. There is a 6% sales tax in his state and a combi
2 answers:
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Answer:
<em>H₀</em>: <em>μ</em>₁ = <em>μ</em>₂ vs, <em>Hₐ</em>: <em>μ</em>₁ > <em>μ</em>₂.
Step-by-step explanation:
A two-sample <em>z</em>-test can be performed to determine whether the claim made by the owner of pier 1 is correct or not.
It is provided that the weights of fish caught from pier 1 and pier 2 are normally distributed with equal population standard deviations.
The hypothesis to test whether the average weights of the fish in pier 1 is more than pier 2 is as follows:
<em>H₀</em>: The weights of fish in pier 1 is same as the weights of fish in pier 2, i.e. <em>μ</em>₁ = <em>μ</em>₂.
<em>Hₐ</em>: The weights of fish in pier 1 is greater than the weights of fish in pier 2, i.e. <em>μ</em>₁ > <em>μ</em>₂.
The significance level of the test is:
<em>α</em> = 0.05.
The test is defined as:
The decision rule for the test is:
If the <em>p</em>-value of the test is less than the significance level of 0.05 then the null hypothesis will be rejected and vice-versa.
Answer:
At h=0.1 value od y(1.2)=15.920, and at h=0.05, y(1.2)=16.523.
Step-by-step explanation:
Given,
with y(1)=9.
That is when x=1 then y=9 initially.
To find value of y= f(x,y) at when y=0.1 and y=0.05 we will use c-programme of Eular method we get, for h=0.1 :
#include<stdio.h>
float fun(float x, float y)
{
float f;
f=2x+3y+1;
return f;
}
main()
{
float a,b,x,y,h,t,k;
printf("\ Enter x0,y0,h,xn:");
scanf("% f % f % f % f ", & a, &b, &h, &t);
x=a;
y=b;
printf("\n x\t y\n");
while (x<=t)
{
k=h*fun(x,y);
x=x+h;
y=y+k;
printf("%0.3f\%0.3f\n",x,y);
}
}
By putting value x0=1, y0=9, h=0.1, xn=1.2 we will get results as, y(1.2)=15.920.
Again by putting values x0=1, y0=9, 0.h=05, xn=1.2 we get y(1.2)=16.523.
Answer:
Refer the attached figure.
Step-by-step explanation:
Given : Here are Barry Bonds's home-run totals, mostly for the San Francisco Giants, during the years 1991 - 2005
The data A={25, 34, 46, 37, 33, 42, 40, 37, 34, 49, 73, 46, 45, 45}
To find : Modified box plot for this distribution?
Solution :
Arranging the data from lowest to highest,
{25,33,34,34,37,37,40,42,45,45,46,46,49,73}
Find the median of the data
As the data is even numbers so the median is
Median = 41
For Box plot Graph,
Plotting the Box plot of the data.
Refer the attached figure below.
