Ray Cupple bought a basic car costing $26,500.00, with options costing $725.00. There is a 6% sales tax in his state and a combi
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Answer:
Length A of the magazine garden is 28 feet is true.
Length B of the Magazine garden is 17.5 feet is true.
Length C of the Magazine garden is 35 feet is true.
Step-by-step explanation:
Please refer the attached figure.
Given:-
Magazine Scale is 1 inch = 3.5 feet.
Imogen's scale is 2 inches = 6 feet,
Therefore Imogen's scale is 1 inch = 3 feet.
In Triangle ABC,
side a = 8 inches, side b= 5 inches, side c= 10 inches.
To find:- The correct 3 options(actual size of sides of triangle ABC).
Solution:-
In triangle ABC,
Let,
AB=side a =8 inches
BC=side b =5 inches
AC=side c= 10 inches
Now, as per the given scale's of Magazine and Imogen's we can find the actual sizes.
Length A as per Magazine scale (1 inch = 3.5 feet) is,
-------------(as per scale)
and Length A as per Imogen's scale(1 inch =3 feet) is,
AB = side a
-------------(as per scale)
Therefore Length A of the magazine garden is 28 feet is true.
Now, Length B as per Magazine scale (1 inch = 3.5 feet) is,
BC = side b
Length B as per Imogen's scale (1 inch = 3 feet) is,
BC = side b
Therefore Length B of the Magazine garden is 17.5 feet is true.
Now, Length C as per Magazine scale (1 inch = 3.5 feet) is,
AC = side c
Length B as per Imogen's scale (1 inch = 3 feet) is,
AC = side c
Therefore Length C of the Magazine garden is 35 feet is true.
Answer:
Step-by-step explanation:
Hello!
You have the variable
X: Area that can be painted with a can of spray paint (feet²)
The variable has a normal distribution with mean μ= 25 feet² and standard deviation δ= 3 feet²
since the variable has a normal distribution, you have to convert it to standard normal distribution to be able to use the tabulated accumulated probabilities.
a.
P(X>27)
First step is to standardize the value of X using Z= (X-μ)/ δ ~N(0;1)
P(Z>(27-25)/3)
P(Z>0.67)
Now that you have the corresponding Z value you can look for it in the table, but since tha table has probabilities of , you have to do the following conervertion:
P(Z>0.67)= 1 - P(Z≤0.67)= 1 - 0.74857= 0.25143
b.
There was a sample of 20 cans taken and you need to calculate the probability of painting on average an area of 540 feet².
The sample mean has the same distribution as the variable it is ariginated from, but it's variability is affected by the sample size, so it has a normal distribution with parameners:
X[bar]~N(μ;δ²/n)
So the Z you have to use to standardize the value of the sample mean is Z=(X[bar]-μ)/(δ/√n)~N(0;1)
To paint 540 feet² using 20 cans you have to paint around 540/20= 27 feet² per can.
c.
P(X≤27) = P(Z≤(27-25)/(3/√20))= P(Z≤2.98)= 0.999
d.
No. If the distribution is skewed and not normal, you cannot use the normal distribution to calculate the probabilities. You could use the central limit theorem to approximate the sampling distribution to normal if the sample size was 30 or grater but this is not the case.
I hope it helps!