The coordinate pairs (-5, -11), (0, -1), and (5, 9) are solutions to which function?

1 answer:

7 0

You have to probe each function until you find the right one.

1) f(x) = 3x - 1
x f(x) = 3x - 1

-5        3(-5) - 1 = -15 - 1 = - 16 => it is not

2) f(x) = 2x + 1

x     f(x) = 2x + 1

-5        2(-5) + 1 = -10 + 1 = - 9 => it is not

3) f(x) = 3x - 6

x      f(x) = 3x - 6

-5         3(-5) - 6 = - 15 - 6 = - 21 => it is not

4) f(x) = 2x - 1

x     f(x) = 2x - 1

- 5    2(-5) - 1 = -10 - 1 = -11 => point (-5, -11) => right

0       2(0) - 1 = 0 - 1 = - 1 => pont ( 0, - 1) => right

5       2(5) - 1 = 10 - 1 = 9 => point (5, 9) => right

Therefore the answer is the option d. f(x) = 2x - 1

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Answer:

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Step-by-step explanation:

We need to find the expression that is equivalent to the complex number 10+3i.

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Hence, the correct option is (B).

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Answer:

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We also know that, by definition of linear pair postulate, $\angle 3$ and $\angle 1$ are linear pair. Linear pair postulate is a math concept that defines two angles that are adjacent and for a straight angle, which is equal to 180°.

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If we substitute $\angle 5$ for $\angle 1$ , we have $m \angle 3 + m \angle 5 = 180\°$ , which means that $\angle 3$ and $\angle 5$ are also supplementary by definition.