Question

What is the surface area of the regular pyramid below?

Answer 1

Answer:

$\boxed{B\:\:\:864\:units^2}$

Step-by-step explanation:

The surface area of the regular pyramid is the sum of the area of the 4 triangular faces and the area of the square base.

The area of the triangular faces is

$=4\times \frac{1}{2}\times base\times height$

$=4\times \frac{1}{2}\times 16\times 19$

$=2\times 16\times 19$

$=608\:units^2$

The area of the square base

$=l^2$

$=16^2$

$=256\:units^2$

The surface area of the regular polygon is therefore;

$=608+256$

$=864\:units^2$

Answer 2

864 units^2   

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