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makkiz [27]
2 years ago
8

Use inverse variation equation to fill the table.

Mathematics
2 answers:
ASHA 777 [7]2 years ago
7 0

The correct answers to the question above includes:

a=.1
b=20.775
c=0.02


mestny [16]2 years ago
4 0

Answer:

Inverse Variation states that a relationship between two variables x and y, represent an inverse variation if it can be expressed in the form of:

i.e y \propto \frac{1}{x}  or y = \frac{k}{x} ;  where k is the constant of variation.

In the given problem :

P=\frac{8.31}{v} where v is the volume(liters) and P is the pressure.

We have the value of the constant K

i.e  K = 8.31

so, Pv = 8.31                  ......[1]

From the given table;

if v = 83.1 liters and P= a ;

Substitute in [1] to solve for a;

83.1a = 8.31

Simplify:

a = 0.1 kilopascals

Similarly,

if v = b liters and P = 0.4 kilopascals

Substitute in [1] to solve for b;

0.4b = 8.31

Simplify:

b = 20.775 liters

and

if v = 415.5 liters and P =c ;

Substitute in [1] to solve for c;

415.5c = 8.31

Simplify:

c = 0.02 kilopascals .

Therefore, value of:

a = 0.1

b = 20.775

c = 0.02


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In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

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This proportion is 1 subtracted by the pvalue of Z when X = 131. So

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7 0
2 years ago
-3^(-x)-6=-3^x+10<br><br>Solve the equation below for x by graphing plz
vitfil [10]
To graph it, just graph y=-3^{-x}-6 and y=-3^x+10 and see where they intersect

I would like to solve it by using math and not graphing
if you don't want to see the math, just don't scroll down
the graphical meathod is above, first line, just read it

hmm
multiply both sides by -1
3^{-x}+6=3^x-10
multiply both sides by 3^x
3^0+6(3^x)=3^{2x}-10(3^x)
1+6(3^x)=3^{2x}-10(3^x)
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use u subsitution
u=3^x
we can rewrite it as
0=u^2-16u-1
now factor
I mean use quadratic formula
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so for 0=u^2-16u-1, a=1, b=-16, c=-1
u=\frac{-(-16)+/-\sqrt{(-16)^2-4(1)(-1)}{2(1)}
u=8+/-\sqrt{65}
remember that u=3^x so u>0
if we have u=8+√65, it's fine, but u=8-√65 is negative and not allowed
so therfor
u=8+\sqrt{65}=3^x
8+\sqrt{65}=3^x
if you take the log base 3 of both sides you get
log_3(8+\sqrt{65})=x
if you use ln then
ln(8+\sqrt{65})=xln(3)
then
\frac{ln(8+\sqrt{65})}{ln(3)}=x

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