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Korvikt [17]
2 years ago
4

Can someone help me please

Mathematics
1 answer:
Bumek [7]2 years ago
5 0
Yes, -7 is greater than -10 so I think that your answer would be B, that -7 is locates to the right of -10.hope this helps! Have a blessed day!
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Select the correct answer. Gary throws a parachute toy from the roof of a building which has a height of 96 feet. The toy reache
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Answer:

Z

Step-by-step explanation:

The height needs to start at 96

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2 years ago
The pizza shop offers a 15 percent discount for veterans and senior citizens. If the price of a pizza is $12, how would you find
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All you would do is times 12 by .15 or 15% you get 1.8 then all you do is 12 minus 1.8 you get $10.20 that is the price of a discounted pizza 

I hope this helps


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2 years ago
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Hank bought 5 meters of ribbon for $4. The ribbon costs -$0.008, 0.08, $0.8- per -millimeter, centimeter, kilometer-. Choose one
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To determine the cost of each meter of the ribbon, we divide the cost for 5 meters of ribbon by 5. That is,
                                        x = $4 / 5
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                                = $0.0008/mm
5 0
2 years ago
y = A system of equations. y equals StartFraction one-half EndFraction x minus 6. x equals negative 4.x – 6 x = –4 What is the s
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Answer: (-4,-8)

Step-by-step explanation: I got a 100% on the quiz

8 0
2 years ago
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Square $ABCD$ has area $200$. Point $E$ lies on side $\overline{BC}$. Points $F$ and $G$ are the midpoints of $\overline{AE}$ an
Charra [1.4K]

1. Consider square ABCD. You know that  

A_{ABCD}=AD^2=200,

then

AB=BC=CD=AD=10\sqrt{2}.

2. Consider traiangle AED. F is mipoint of AE and G is midpoint of DE, then FG is midline of triangle AED. This means that

FG=\dfrac{AD}{2}=\dfrac{10\sqrt{2} }{2}=5\sqrt{2}.

3. Consider trapezoid BFGC. Its area is

A_{BFGC}=\dfrac{FG+BC}{2}\cdot h, where h is the height of trapezoid and is equal to half of AB. Thus,

A_{BFGC}=\dfrac{FG+BC}{2}\cdot \dfrac{AB}{2}=\dfrac{5\sqrt{2}+10\sqrt{2}}{2}\cdot \dfrac{10\sqrt{2}}{2}=75.

4.

A_{BFGC}=A_{BFGE}+A_{EGC},\\A_{EGC}=A_{BFGC}-A_{BFGE}=75-34=41.

5. Note that angles EGC and CGD are supplementary and

\sin \angle CGD=\sin \angle EGC.

Then

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Answer: A_{CGD}=41.

8 0
2 years ago
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