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2 years ago

CDEF maps to JKLM with the transformations (x, y) --> (5x, 5y) --> (x-4, y-4). What is the value of EF/LM?

1 answer:

4 0

Given that CDEF maps to JKLM ,with the transformation (x, y) ---> (5x, 5y) ---> (x - 4, y - 4).

This means that each part of CDEF is increased by a factor of 5 and then moved 4 places to the left to get JKLM.

Thus, the ratio of any part of CDEF to the corresponding part in JKLM is 1 : 5.

Therefore, EF / LM = 1 / 5.

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Identify two numbers less than 20 with the most factors

Anastaziya [24]

Answer

18 and 12

Explanation

Factor is a number or algebraic expression that divides another number or expression evenly that is with no remainder.

Odd number have few factors so the can't be the answer.

WE are going to try the even numbers.

18 ⇒ 18, 9, 6, 3, 2, 1

16 ⇒ 16, 8, 4, 2, 1

12 ⇒ 12, 6, 4, 3, 2, 1

10 ⇒ 10, 5, 2, 1

Other number less than 10 has factors less than 5.

It can be seen from above that 18 and 12 have the most factors.

3 0

2 years ago

Read 2 more answers

Kenny types 280 words. How long did he type for? A.4 B. 5 C.6 D. 7

zlopas [31]

Are you sure you didn’t miss anything while writing the question?

Cause we have nothing to go off. Everybody types differently so there is no way for us to say how long he typed for, unless we were given aprox how many words he wrote in a minute or something

5 0

2 years ago

Read 2 more answers

Find the dimensions of a deck which will have railings on only three sides. There is 28 m of railing available and the deck must

Roman55 [17]

Answer:

The largest possible area of the deck is 87.11 m² with dimensions;

Width = 9.33 m

Breadth = 9.33 m

Step-by-step explanation:

The area of a given dimension increases as the dimension covers more equidistant dimension from the center, which gives the quadrilateral with largest dimension being that of a square

Given that the railings will be placed on three sides only and the third side will cornered or left open, such that the given length of railing can be shared into three rather than four to increase the area

The length of the given railing = 28 m

The sides of the formed square area by sharing the railing into three while the fourth side is left open are then equal to 28/3 each

The area of a square of side s = s²

The largest possible area of the deck = (28/3)² = 784/9 = 87.11 m² with dimensions;

Width = 28/3 m = 9.33 m

Breadth = 28/3 m = 9.33 m.

5 0

2 years ago

Two students from a group of eight boys and 12 girls are sent to represent the school in a parade. If the students are chosen at

kari74 [83]

Answer:

Step-by-step explanation:

* Lets explain how to find the probability of an event

- The probability of an Event = Number of favorable outcomes ÷ Total

number of possible outcomes

- P(A) = n(E) ÷ n(S) , where

# P(A) means finding the probability of an event A

# n(E) means the number of favorable outcomes of an event

# n(S) means set of all possible outcomes of an event

- Probability of event not happened = 1 - P(A)

- P(A and B) = P(A) . P(B)

* Lets solve the problem

- There is a group of students

- There are 8 boys and 12 girls in the group

∴ There are 8 + 12 = 20 students in the group

- The students are sent to represent the school in a parade

- Two students are chosen at random

∴ P(S) = 20

- The students that chosen are not both girls

∴ The probability of not girls = 1 - P(girls)

∵ The were 20 students in the group

∵ The number of girls in the group was 12

∴ The probability of chosen a first girl = 12/20

∵ One girl was chosen, then the number of girls for the second

choice is less by 1 and the total also less by 1

∴ The were 19 students in the group

∵ The number of girls in the group was 11

∴ The probability of chosen a second girl = 11/19

- The probability of both girls is P(1st girle) . P(2nd girl)

∴ The probability of both girls = (12/20) × (11/19) = 33/95

- To find the probability of both not girls is 1 - P(both girls)

∴ P(not both girls) = 1 - (33/95) = 62/95

* The probability that the students chosen are not both girls is 62/95

3 0

2 years ago

Read 2 more answers

Bilal's fishing line was on a spool with a radius of 4 \text{ cm}4 cm4, start text, space, c, m, end text. Suddenly, a fish pull

Fantom [35]

Answer:

The distance the fish pulled the fishing line is 401.92 cm.

Step-by-step explanation:

Given:

Radius of fishing spool = 4 cm.

Fish pulled on the line, and the spool spun 16 times before Bilal began to reel in the fish.

Now, to find the distance the fish pulled the fishing line.

So, to get the circumference of the spool first we put formula:

Radius(r) = 4 cm.

Value of π = 3.14.

$Circumference = 2\pi r$

$Circumference=2\times 3.14\times 4$

$Circumference=25.12\ cm.$

As given, fish pulled on the line, and the spool spun 16 times before Bilal began to reel in the fish.

Now, to get the distance the fish pulled the fishing line, we multiply 16 with the circumference:

$16\times 25.12\\\\=401.92\ cm.$

Therefore, the distance the fish pulled the fishing line is 401.92 cm.

3 0

2 years ago