When the concentration is expressed in molality, it is expressed in moles of solute per kilogram of solvent. Since we are given the mass of the solvent, which is water, we can compute for the moles of solute NaNO3.
0.5 m = x mol NaNO3/0.5 kg water
x = 0.25 mol NaNO3
Since the molar mass of NaNO3 is 85 g/mol, the mass is
0.25 mol * 85 g/mol = 21.25 grams NaNO3 needed
Identify each of the following as a product or a coefficient in reaction below
<h2> 2H^+ + CO3^2- → H2O + CO2</h2><h2 /><h2 /><h3> <u><em>reactant are</em></u></h3><h2> H^+ and CO3^2-</h2>
<u><em>Reason: </em></u>Reactant of a chemical reaction are found in the left side. They are initially present in a chemical reaction which are consumed to form product.
<h3> <em><u>Product are</u></em></h3>
H2O and CO2
<u><em>Reason</em></u>: They are found in the right side of the reaction. Product are produced in a chemical reaction.
<em><u>coefficient</u></em>
<em><u> </u></em><em><u> </u></em>is 2
- Coefficient is the number found in front of a formula.
- Therefore 2 is the coefficient since it is found in front of H^+
Answer: For transverse waves, the waves move in perpendicular direction to the source of vibration.
For longitudinal waves, the waves move in parallel direction to the source of vibration .
They are similar within the sense that energy is transferred within the kind of waves.
Explanation:
1) State the equation that represents the chemical reaction
P2O5 + 3H2O → 2H3PO4
2) State the molar ratios: 1 mol P2O5 : 3 mol H2O : 2 mol H3PO4
3) Use the proportions 3molH2O / 2 mol H3PO4
0.729 mol H3PO4 * [ 3 mol H2O / 2 mol H3PO4] = 1.094 mol H2O
Answer: 1.094 mol of water
Let me give you an example. Lets say that we have an amount of Ba(OH)2 compared to H2SO4. And let's say that the Ba(OH)2 dissociates as Ba+2 + 2 OH-. H2SO4 dissociates as 2 H+ + SO4-2. So, what happens here is that w<span>hen the conductivity is at a minimum it means that stoichiometric amounts of Ba(OH)2 and H2SO4 are present and the only materials you can find there in the reaction vessel are H2O and BaSO4. That is why it conduct more before and after this minimum point</span>
