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klemol [59]
1 year ago
14

A man pours some hot coffee into a small cup from a large jug that contains enough coffee for several cups. Which statement corr

ectly compares the coffee in the cup and in the jug?
A.
The coffee in the cup has a lower temperature than the coffee in the jug because there's less of it.
B.
The coffee in the jug absorbs more heat than the coffee in the cup because there's more of it.
C.
The coffee in the jug has more thermal energy than the coffee in the cup.
D.
The coffee in the cup and the coffee in the mug have the same amount of internal energy.
E.
The coffee in the cup has more thermal energy, but the coffee in the jug has more internal energy.
Chemistry
2 answers:
antiseptic1488 [7]1 year ago
8 0
I would say the answer is C) because the thermal energy of the coffee going into the cup has to level out until the cup gets warmer and the coffee gets cooler, and they reach the same temperature.Meaning that the jug which has already been at the same temperature(we can assume based on the verbiage “the coffee was poured from the jug to the cup”) which would give the jug more thermal energy.
Delicious77 [7]1 year ago
6 0

Answer: Your answer would be C. the coffee in the jug has more thermal energy than the coffee in the cup

Explanation:

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maxonik [38]
Answer 1:
Equilibrium constant (K) mathematically expressed as the ratio of the concentration of products to concentration of reactant. In case of gaseous system, partial pressure is used, instead to concentration.

In present case, following reaction is involved:

                        2NO2    ↔      2NO + O2

Here, K = \frac{[PNO]^2[O2]}{[PNO2]^2}

Given: At equilibrium, <span>PNO2= 0.247 atm, PNO = 0.0022atm, and PO2 = 0.0011 atm
</span>
Hence,  K = \frac{[0.0022]^2[0.0011]}{[0.247]^2}
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Thus, equilibrium constant of reaction = 8.727 X 10^-8
.......................................................................................................................

Answer 2:
Given: <span>PNO2= 0.192 atm, PNO = 0.021 atm, and PO2 = 0.037 atm.

Therefore, Reaction quotient = </span>\frac{[PNO]^2[O2]}{[PNO2]^2}
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1 year ago
The mass of radium-226 in a sample is found to have decreased from 45.00g to 5.625g in a period of 4800 years.From this informat
yan [13]

Answer:

Half life = 1600 years

Explanation:

Given data:

Total mass of sample = 45.00 g

Mass remain = 5.625 g

Time period = 4800 years

Half life of radium-226 = ?

Solution:

First of all we will calculate the number of half lives passes,

At time zero 45.00 g

At first half life = 45.00 g/ 2= 22.5 g

At 2nd half life = 22.5 g/ 2 = 11.25 g

At 3rd half life = 11.25 g/ 2= 5.625 g

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Half life = 4800 years / 3

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1 year ago
A hydrogen filled balloon has a bolume of 8.3 L at 36 C and 751 torr. How many moles of hydrogen are inside the balloon?
alina1380 [7]

Answer:

0.33 mol

Explanation:

Given data:

Volume of balloon = 8.3 L

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Pressure = 751 torr

Number of moles of hydrogen = ?

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Formula:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

PV  = nRT

0.988 atm × 8.3 L  = n × 0.0821 atm.L/ mol.K  × 300 K

8.2 atm.L = n × 24.63 atm.L/ mol

n = 8.2 atm.L / 24.63 atm.L/ mol

n = 0.33 mol

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timurjin [86]

Answer:

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It attributes like the age , gender , educational qualification and religion , plays a major role in the research .

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