Answer:
d = 70.5 mm
Explanation:
given,
length of pipe = 305 m
discharge rate = 150 gal/min
pipe diameter = ?
1 gal/min = 6.30902 × 10⁻⁵ m³/s
150 gal/min = 150 × 6.30902 × 10⁻⁵ m³/s
= 9.46 × 10⁻³ m³/s
Q = A V
f = 0.048 from moody chart using P/D = 0.00015
d = 70.5 mm
Diameter of the pipe is equal to 70.5 mm
Answer:
A.0.20M
Explanation:
c 1 V 1 = c 2 V 2
Initial Volume, V1 = 200 mL
Final Volume, V2 = 200 + 400 = 600 mL
Initial Concentration, c1 = 0.60 M
Final Concentration, c2= ?
Solving for c2;
c2 = c1v1 / v2
c2 = 0.60 * 200 / 600
c2 = 0.20M
Bronze alloy and porcelain dentures
The total energy in a system due to the temperature and pressure per unit mass in that system is known as specific enthalpy. It is used in thermodynamic equations when one desires to know the energy for a given single unit mass of a component.
Specific enthalpy is calculated by the equation:
H = U + PV
in the given case, Specific volume = 4.684 cm³/g = 149.888 cm³/g moles = 149.888 × 10⁻³ J/g moles
Specific internal energy (U) is 1706 J/mol and pressure is 41.64.
H = 1706 + 41.64 × 149.888 × 10⁻³ × 101.3 joules
= 2428 joules / mole
<h3>The average atomic mass of Iodine : 126.86 amu</h3><h3>Further explanation</h3>
Given
80% 127I, 17% 126I, and 3% 128I.
Required
The average atomic mass
Solution
The elements in nature have several types of isotopes
Atomic mass is the average atomic mass of all its isotopes
Mass atom X = mass isotope 1 . % + mass isotope 2.% + ... mass isotope n.%
Atomic mass of Iodine = 0.8 x 127 + 0.17 x 126 + 0.03 x 128
Atomic mass of Iodine = 101.6 + 21.42 + 3.84
Atomic mass of Iodine = 126.86 amu
