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ivolga24 [154]
2 years ago
6

Use le chatelier's principle to explain why the solubility of iodine in water increases as the concentrations of potassium iodid

e increases
Chemistry
1 answer:
charle [14.2K]2 years ago
3 0
Answer is: increasing the concentration of the iodide ions creates disturbance. According to Le Chatelier’s principle, the system will react in a way that tends to reduce the disturbance. The reaction shift in the forward direction, to make more triiodide ions and consume some of the added iodide with aqueous iodine. This causes more solid iodine to dissolve in the solution (increasing concentration).
Reaction: I₂(aq) + I⁻ (aq) ⇄ I₃⁻(aq).
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his is the chemical formula for chromium(III) nitrate: . Calculate the mass percent of oxygen in chromium(III) nitrate. Round yo
Alinara [238K]

Answer:

\%\ Composition\ of\ iron=69.92\ \%

Explanation:

Percent composition is percentage by the mass of element present in the compound.

The formula for chromium(III) nitrate is Cr(NO_3)_3

Molar mass of chromium(III) nitrate = 238.011 g/mol

1 mole of chromium(III) nitrate contains 9 moles of oxygen

Molar mass of oxygen = 16 g/mol

So, Mass= Molar mass*Moles = 16*9 g = 144 g

\%\ Composition\ of\ iron=\frac{Mass_{iron}}{Total\ mass}\times 100

\%\ Composition\ of\ iron=\frac{144}{238.011}\times 100

\%\ Composition\ of\ iron=69.92\ \%

5 0
2 years ago
The molar mass of oxygen gas (O2) is 32.00 g/mol. The molar mass of C3H8 is 44.1 g/mol. What mass of O2, in grams, is required t
Ira Lisetskai [31]
The reaction formula of this is C3H8 + 5O2 --> 3CO2 + 4H2O. The ratio of mole number of C3H8 and O2 is 1:5. 0.025g equals to 0.025/44.1=0.00057 mole. So the mass of O2 is 0.00057*5*32=0.0912 g.
6 0
2 years ago
Which element is used in light bulbs as a filament
mojhsa [17]
<span>The element that is used in light bulbs as a filament is tungsten - this is almost always the case in halogen and incandescent bulbs. Tungsten is chosen for this purpose because of the fact it can withstand temperatures of up to 4,500 degrees, as well as being incredibly flexible.</span>
8 0
2 years ago
vanadium has an atomic mass of 50.9415 amu. it has two common isotopes.one isotopes has a mass of 50.9440 amu and a relative abu
Kaylis [27]

Explanation:

Average atomic mass of the  vanadium = 50.9415 amu

Isotope (I) of vanadium' s abundance = 99.75 %= 0.9975

Atomic mass of Isotope (I) of vanadium ,m= 50.9440 amu

Isotope (II) of vanadium' s abundance =(100%- 99.75 %) = 0.25 % = 0.0025

Atomic mass of Isotope (II) of vanadium ,m' = ?

Average atomic mass of vanadium =

m × abundance of isotope(I) + m' × abundance of isotope (II)

50.9415 amu =50.9440 amu× 0.9975 + m' × 0.0025

m'= 49.944 amu

The atomic mass of isotope (II) of vanadium is 49.944 amu.

5 0
2 years ago
Describe how transpiration and respiration show interactions among Earth's system
stepladder [879]

Earth has 4 systems/ spheres which are known as Lithosphere(land), Biosphere(living things), Hydrosphere(water) and Atmosphere(air).

Transpiration is the process that interact with the Hydrosphere and Respiration is the process that interacts with the Atmosphere.

Transpiration is the process happening in plants which absorb and distribute water through their roots and release water in the form of vapors through their leaves. As this process involves Water, therefore this process interacts with the Hydrosphere.  

Respiration is the process in which plants convert carbon dioxide to oxygen as a part of photosynthesis which was then inhaled by the animals. As this process involves Air, therefore this process interacts with the Atmosphere.

7 0
2 years ago
Read 2 more answers
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