When a polar molecule causes a charge redistribution in a nonpolar molecule, what are the molecules of the mixture most likely e
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Answer:
The estimated feed rate of logs is 14.3 logs/min.
Explanation:
The product of the process is 2000 tons/day of dry wood pulp, of 85 wt% of cellulose. That represents (2000*0.85)=1700 tons/day of cellulose.
That cellulose has to be feed by the wood chips, which had 47 wt% of cellulose in its composition. That means you need (1700/0.47)=3617 tons/day of wood chips to provide all that cellulose.
Th entering flow is wood chips with 45 wt% of water. This solution has an specific gravity of 0.640.
To know the specific gravity of the wood chips we have to write a volume balance. We also know that Mw=0.45*M and Mc=0.55*M.
The specific gravity of the wood chips is 0.494.
The average volume of a log is
The weight of one log is
To provide 3617 ton/day of wood chips, we need
The feed rate of logs is 14.3 logs/min.
Answer :
(1) The theoretical yield of product, is, 1.257 grams.
(2) The percent yield of is, 64.13 %
(3) If the percent yield is calculated to be over 100% then there might be some impurity present in the desired product.
Solution : Given,
Mass of Mg = 0.7542 g
Molar mass of Mg = 24 g/mole
Molar mass of MgO = 40 g/mole
First we have to calculate the moles of Mg.
Now we have to calculate the moles of
The balanced chemical reaction is,
From the reaction, we conclude that
As, 2 mole of react to give 2 mole of
So, 0.03142 moles of react to give 0.03142 moles of
Now we have to calculate the mass of
Theoretical yield of = 1.257 g
Experimental yield of = 0.8922 g
Now we have to calculate the percent yield of
Therefore, the percent yield of is, 70.97 %
If the percent yield is calculated to be over 100% then the product would be greater than 1.257 g which indicates that there might be some impurity present in the desired product.