The number x of bottles of garden plant fungicide sold by a garden center each day was recorded with the following results:
1 answer:
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Answer:
A.) Acceleration = 4.6 m/s^2
B.) Average speed = 47 m/s
Step-by-step explanation:
A.) From the graph, at t = 10s,
Velocity V = 46 m/s
Acceleration a = (change in V)/ time t
a = (46 - 0)/10
a = 46/10 = 4.6 m/s^2
B.) If we estimate the speed at 5 seconds intervals, then we have
Average speed = (36 + 46 + 49 + 50 + 50 +50 + 50) ÷ 7
Average speed = 331/7 = 47.29 m/s
Average speed = 47 m/s
Answer:
The dimensions of the two different rectangular regions are;
1st Arrangement:
W = 4 yards and L = 5 yards or W = 5 yards and L = 4 yards
2nd Arrangement:
W = 2 yards and L = 10 yards or W = 10 yards and L = 2 yards
The perimeter of the two different rectangular regions are;
1st Arrangement:
P₁ = 18 yards
2nd Arrangement:
P₂ = 24 yards
Step-by-step explanation:
Bella is putting down patches of sod to start a new lawn.
She has 20 square yards of sod.
We are asked to provide the dimensions of two different rectangular regions that she can cover with the sod.
Recall that a rectangle has an area given by
Area = W*L
Where W is the width of the rectangle and and L is the length of the rectangle.
Since Bella has 20 square yards of sod,
20 = W*L
There are more than two such possible rectangular arrangements.
Out of them, two different possible arrangements are;
1st Arrangement:
20 = (4)*(5) = (5)*(4)
Width is 4 yards and length is 5 yards or width is 5 yards and length is 4 yards
2nd Arrangement:
20 = (2)*(10) = (10)*(2)
Width is 2 yards and length is 10 yards or width is 10 yards and length is 2 yards
Therefore, the dimensions of two different rectangular regions are;
1st Arrangement:
W = 4 yards and L = 5 yards or W = 5 yards and L = 4 yards
2nd Arrangement:
W = 2 yards and L = 10 yards or W = 10 yards and L = 2 yards
What is the perimeter of each region?
The perimeter of a rectangular shape is given by
P = 2(W + L)
Where W is the width of the rectangle and and L is the length of the rectangle.
The perimeter of the 1st arrangement is
P₁ = 2(4 + 5)
P₁ = 2(9)
P₁ = 18 yards
The perimeter of the 2nd arrangement is
P₂ = 2(2 + 10)
P₂ = 2(12)
P₂ = 24 yards
So the perimeter of the 1st arrangement is 18 yards and the perimeter of the 2nd arrangement is 24 yards.
Note:
Another possible arrangement is,
20 = (1)*(20) = (20)*(1)
Width is 1 yard and length is 20 yards or width is 20 yards and length is 1 yard.
