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pantera1 [17]
2 years ago
5

Javier simplified the expression below. Find and describe the three mistakes he made.

Mathematics
2 answers:
Lilit [14]2 years ago
8 0

Answer:

1.Javier did not write the coefficient raised to power of 3

2.Javier wrote x^4 instead of x^3

3.Javier did divide exponents instead of subtraction of exponents

Step-by-step explanation:

We are given that Javier simplified the expression

(\frac{20x}{5x^8})^{-3}

We have to find three mistakes made by Javier.

(\frac{20x}{5x^8})^{-3}

\frac{(20x)^{-3}}{(5x^8)^{-3}}

\frac{(5x^8)^3}{(20x)^3}

By using property;a^{-x}=\frac{1}{a^x}

\frac{125x^{24}}{8000x^3}

By using property:(ab)^x=a^xb^x

(a^x)^y=a^{xy}

\frac{1}{64}x^{24-3}

By using property\frac{a^x}{a^y}=a^{x-y}

\frac{1}{64}x^{21}

Javier made three mistakes are given below:

1.Javier did not write the coefficient raised to power of 3

2.Javier wrote x^4instead ofx^3

3.Javier did divide exponents instead of subtraction of exponents.

Irina18 [472]2 years ago
7 0

Which of the following did you include in your response?

Javier did not raise the coefficients to the third power

When Javier raised (x^1)^3 to the third power, he wrote that x^4, but it equals x^3.

In the last step, Javier divided the exponents. He should have used the quotient of powers property and subtracted them.

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There is a relationship between confidence interval and standard deviation:
\theta=\overline{x} \pm \frac{z\sigma}{\sqrt{n}}
Where \overline{x} is the mean, \sigma is standard deviation, and n is number of data points.
Every confidence interval has associated z value. This can be found online.
We need to find the standard deviation first: 
\sigma=\sqrt{\frac{\sum(x-\overline{x})^2}{n}
When we do all the calculations we find that:
\overline{x}=123.8\\ \sigma=11.84
Now we can find confidence intervals:
($90\%,z=1.645): \theta=123.8 \pm \frac{1.645\cdot 11.84}{\sqrt{15}}=123.8 \pm5.0\\($95\%,z=1.960): \theta=123.8 \pm \frac{1.960\cdot 11.84}{\sqrt{15}}=123.8 \pm 5.99\\ ($99\%,z=2.576): \theta=123.8 \pm \frac{2.576\cdot 11.84}{\sqrt{15}}=123.8 \pm 7.87\\
We can see that as confidence interval increases so does the error margin. Z values accociated with each confidence intreval also get bigger as confidence interval increases.
Here is the link to the spreadsheet with standard deviation calculation:
https://docs.google.com/spreadsheets/d/1pnsJIrM_lmQKAGRJvduiHzjg9mYvLgpsCqCoGYvR5Us/edit?usp=sharing
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2 years ago
Which graph represents the hyperbola = 1?
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Answer:

131

Step-by-step explanation:

We have to find the graph of the hyperbola whose equation is given as:.We know that the general equation of the hyperbola is given by:where the focus of the hyperbola are at the points:(a,0) and (-a,0).Hence, the focus of the given hyperbola are the points:(3,0) and (-3,0).The figure of the hyperbola is attached to the figure.

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Anna and Lionel share $675 in the ratio 4 : 5 Lionel gives 3/5 of his share of the money to his mother. How much money does Lion
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Step-by-step explanation:

Total share ratio = 4+5 = 9

Lionel's ratio = 5

Lionel's share = (5/9) × 675

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Lionel's mum = (3/5) x 375

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A car insurance company suspects that the younger the driver is, the more reckless a driver he/she is. They take a survey and gr
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Answer:

The confidence interval for the difference in proportions is

-0.028\leq p_1-p_2 \leq 0.096

No. As the 95% CI include both negative and positive values, no proportion is significantly different from the other to conclude there is a difference between them.

Step-by-step explanation:

We have to construct a confidence interval for the difference of proportions.

The difference in the sample proportions is:

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The estimated standard error is:

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The z-value for a 95% confidence interval is z=1.96.

Then, the lower and upper bounds are:

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The confidence interval for the difference in proportions is

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<em>Can it be concluded that there is a difference in the proportion of drivers who wear a seat belt at all times based on age group?</em>

No. It can not be concluded that there is a difference in the proportion of drivers who wear a seat belt at all times based on age group, as the confidence interval include both positive and negative values.

This means that we are not confident that the actual difference of proportions is positive or negative. No proportion is significantly different from the other to conclude there is a difference.

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2 years ago
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