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yanalaym [24]
2 years ago
4

Select all of the following that are potential roots of p(x) = x4 − 9x2 − 4x + 12?

Mathematics
2 answers:
Masja [62]2 years ago
7 0

For any polynomial f(x),  k is a root of the polynomial only if f(k)=0 .

To determine which of the given values is a root of the polynomial ,

p(x)=x^4-9x^2-4x+12,

we just have to evaluate the f(x) for each of these values and see if the output is zero.

f(-2)=(-2)^4-9(-2)^2-4(-2)+12=16-36+8+12=0.\\f(2)=(2)^4-9(2)^2-4(2)+12=16-36-8+12=-16.

Since f(2)=-16 , we know that x=2  is  not a root of this polynomial.

Since f(-2)=0 , we know that x=-2  is a root of this polynomial.


jeyben [28]2 years ago
4 0

Answer:

p(-2)= 0

p(2)= -16

the value is -2

Step-by-step explanation:


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the time taken by a student to the university has been shown to be normally distributed with mean of 16 minutes and standard dev
Naya [18.7K]

Answer:

a) 2.84% probability that he is late for his first lecture.

b) 5.112 days

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 16, \sigma = 2.1

a. Find the probability that he is late for his first lecture.

This is the probability that he takes more than 20 minutes to walk, which is 1 subtracted by the pvalue of Z when X = 20. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{20 - 16}{2.1}

Z = 1.905

Z = 1.905 has a pvalue of 0.9716

1 - 0.9716 = 0.0284

2.84% probability that he is late for his first lecture.

b. Find the number of days per year he is likely to be late for his first lecture.

Each day, 2.84% probability that he is late for his first lecture.

Out of 180

0.0284*180 = 5.112 days

4 0
2 years ago
A segment has endpoints A (-1, 1) and B (8, 4) . If the segment is divided into four equal parts, the coordinates of the point c
riadik2000 [5.3K]

Line is divided into 4 equal parts.

we have to find a point which is closest to point A.

So that means required point P(x,y) is at 1 unit away from A(-1,1) and 3 unit away from B(8,4)

Now we just need to use section formula to get the coordinate of required point using m1=1 and m2=3

\left ( \frac{m_1x_2+m_2x_1}{m_1+m_2}  , \frac{m_1y_2+m_2y_1}{m_1+m_2} \right )

= \left ( \frac{1*8+3*(-1)}{1+3}  , \frac{1*4+3*1}{1+3} \right )

= \left ( \frac{8-3}{4}  , \frac{4+3}{4} \right )

= \left ( \frac{5}{4}  , \frac{7}{4} \right )

So the final answer is \left ( \frac{5}{4}  , \frac{7}{4} \right ).

6 0
2 years ago
Read 2 more answers
People at the state fair were surveyed about which type of
Ronch [10]

Answer:

Step-by-step explanation:

You would require the table with the number of males and females who prefer either pink or yellow lemonade at the state fair.

                      Pink Lemonade         Yellow Lemonade       TOTAL

 

Male                    156                                104                          260

 

Female                  72                               48                          120

 

TOTAL                 228                               152                         380

P(pink lemonade | female) = 72 / (48 + 72) = 72 / 120 = 0.6

P(pink lemonade) = (156 + 72) / (156 + 72 + 104 + 48) = 228 / 380 = 0.6

Therefore, The event "prefers pink lemonade" and "female" are independent because P(pink lemonade | female) = P(pink lemonade) = 0.6

6 0
2 years ago
Can somone give me the answer to 2 x 0
marshall27 [118]
Any number times 0 is going to equal 0
8 0
2 years ago
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Which shows one way to determine the factors of 12x3 – 2x2 + 18x – 3 by grouping?
AleksAgata [21]

we are given

12x^3-2x^2+18x-3

Firstly, we will split terms

2x^2*6x-1*2x^2+3*6x-1*3

We can group first two and last two terms

(2x^2*6x-1*2x^2)+(3*6x-1*3)

we can see that 2x^2 is common in first two terms

and 3 is common in last two terms

so, we can factor factor out 2x^2 from first group and 3 from second group

we get

=2x^2(6x-1)+3(6x-1)

we can see that each terms are multiple of 6x-1

so, we can factor out 6x-1

so, we get

12x^3-2x^2+18x-3 =(2x^2+3)(6x-1)............Answer


4 0
2 years ago
Read 2 more answers
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