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Zolol [24]
2 years ago
11

An air show is scheduled for an airport located on a coordinate system measured in miles. The air traffic controllers have close

d the airspace, modeled by a quadratic equation, to non-air show traffic. The boundary of the closed airspace starts at the vertex at (10, 6) and passes through the point (12, 7). A commuter jet has filed a flight plan that takes it along a linear path from (–18, 14) to (16, –13). Which system of equations can be used to determine whether the commuter jet’s flight path intersects the closed airspace?
THESE ARE THE MULTIPLE CHOICE
please i need help nowww

Mathematics
1 answer:
bixtya [17]2 years ago
4 0
<span>Which system of equations can be used to determine whether the commuter jet’s flight path intersects the closed airspace?

 The answer is: The system of equations number three:
</span>
 y=1/4(x-10)²+6  (i)
 y=(-27/34)x-5/17  (ii)
<span>
 The reason is shown below:
</span><span>
 -The boundary of the closed airspace: (10,6); (12,7)
</span>
 -Linear path of the <span>commuter jet: (-18,14) to (16,-13)

 y=1/4(x-10)</span>²+6  (i)
 y=(-27/34)x-5/17  (ii)

 The first equation represents the boundary of the closed airspace, because the points (10,6) and (12,7) are contained in the equation:

 -For (10,6), we have:

 (i) 1/4(10-10)²+6
 6=6 (The equation is satisfied)

 -For (12,7):

 7=1/4(12-10)²+6
 7=4/4+6
 7=1+6
 7=7 (The equation is satisfied)

 The equation (ii) represents the path of the commuter jet, because the points (-18,14) and (16,-13) are contained in the equation:

 -For(16,-13):

 -13=(-27/34)x16-5/7
 -13=-13 (The equation is satisfied)

 -For (-18,14):

 14=(-27/34)x(-18)-5/7
 14=14 (The equation is satisfied)

 Therefore, by resolving the system of equations, we know that the commuter jet’s flight path intersects the closed airspace.
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Consider a single spin of the spinner.
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Answer:

"landing on a shaded portion and landing on a 3"

"landing on an unshaded portion and landing on a number less than 2 "

Step-by-step explanation:

Mutually exclusive means the events will have no intersection.

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"landing on a shaded portion and landing on an even number"

Landing on a shaded portion would be 1 or 4.

Landing on an even number would be 2 or 4.

There is an intersection (they contain a common element), the 4.

These events are not mutually exclusive.

Let's look at your second choice:

"landing on a shaded portion and landing on a number greater than 3"

Landing on a shaded portion would be 1 or 4.

Landing on a number greater than 3 would be just 4.

There is an intersection; they both contain 4.

These events are not mutually exclusive.

Let's look at your third choice:

"landing on a shaded portion and landing on a 3"

Landing on a shaded portion would be 1 or 4.

Landing on 3 would just be 3.

There is no common elements in the lists listed.  These events have no intersection.

These events are mutually exclusive.

Let's look at your fourth choice:

"landing on an unshaded portion and landing on an odd number"

Landing on a unshaded portion would be 2 or 3.

Landing on an odd number would be 1 or 3.

There is an intersection; they both have 3 in common.

These events are not mutually exclusive.

Let's look at your fifth choice:

"landing on an unshaded portion and landing on a number less than 2 "

Landing on an unshaded portion would 2 or 3.

Landing on a number less than 2 would be 1.

There is no intersection.

These events are mutually exclusive.

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2 years ago
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A boy lost 55% of his pocket money.if he had 67½kobo left,how much was his pocket money?​
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Answer:

100 kobo

Step-by-step explanation:

100%-55%=45%                                                                                                       45%=67 and 1/2                    what about                                                                100%=?                                                                                                                      You cross multiply=  <u>100%× 67</u><u>1/2</u>

                                     45%                                                                                   =                           =  <u>100%× 135 ×1 </u>                                                                            =                                          2      45%                                                                         =                           = 50× 2 = 100                                                                           100 ÷2=50                                                                                                             135÷45=2                                                                                                                % cancelled %                                                                                                         So the final answer =    100

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A bridge is rated to a capacity of 100 British tons. What is the maximum weight the bridge can support in kilograms? (Round to t
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Maximum weight the bridge can support in kilograms is 101696

Step-by-step explanation:

  • Step 1: Given capacity of bridge = 100 British tons. Find how many kilograms are equivalent to 1 British ton.

1 British ton = 2240 pounds

1 pound = 0.454 kg

⇒ 1 British ton = 2240 × 0.454 kg = 1016.96 kg

  • Step 2: Find how many kilograms are in 100 British tons.

⇒ 100 × 1016.96 = 101696

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