Answer:
The miRNAs act as post-transcriptional silencers, as they are similar to specific mRNAs and regulate their stability and translation. They are small endogenous non-coding ribonucleic acid (RNA) molecules, with about 22 nucleotides, which act as regulators of gene expression in plants and animals, at the post-transcriptional level through the cleavage of a target messenger RNA (mRNA) or repression of translation.
In general, most miRNA genes are transcribed by RNA polymerase II in the nucleus in primary miRNAs (pri-miRNAs). Individually, a pri-miRNA can produce a single miRNA or contain groups of two or more miRNAs that are processed from a common primary transcript. These long pri-miRNA are cleaved by a complex comprising the double-stranded RNAse III enzyme (DROSHA) and its essential cofactor, the binding protein DGCR8 (DiGeorge Syndrome Critical Region 8 protein) in mammals. DROSHA contains two domains of RNAse III, each of which cleaves a strand of the RNA resulting in the precursor microRNA (pre-miRNA) with about 70 base pairs, which contains a double-stranded stretch and a single-stranded loop, forming a structure in clamp. The pre-miRNA is exported to the cytoplasm by the protein exportin-5 (XPO-5), where it is cleaved by DICER1, an RNAse III that assesses the 3 'and 5' ends of the pre-miRNA, generating a mature miRNA with about 22 nucleotides. The processing of pre-miRNA by Dicer promotes the unfolding of the RNA duplex in the form of a clamp. The position in the formation of the clamp can also influence the choice of tape.
Explanation:
It converts it into electrical energy. Hope that helps :D
Answer:
A
Explanation:
The correct answer would be that <u>the cell was submerged in a hypertonic solution.</u>
<em>A hypertonic solution is a solution with a higher concentration of solutes than that of the cytosol of a cell suspended in it. When a cell is suspended in a hypertonic solution, water moves osmotically from the cytosol to the hypertonic solution. This causes the cytoplasm to collapse and the cell becomes flaccid. </em>
The correct option is A.
Answer:
300
Explanation:
We want to estimate the population of 1000m2 but in our sample of 100m2 we found 30 organism and we know that there are ten 100m2 in 1000m2 meaning there is an estimate population of 300 resulting from 30 per 100m2 sample X 10 [which is the total number of 100m2 in 1000m2].
