answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
yulyashka [42]
2 years ago
12

6. How could you change the simulation to generate data for three pets? Result Frequency Heads, Heads 9 Heads, Tails 14 Tails, H

eads 18 Tails, Tails 9 Total 50
PLEASE HELP WILL GIVE BRAINLYEST
Mathematics
1 answer:
ArbitrLikvidat [17]2 years ago
8 0
9 plus 14 plus 18 plus 9 is 50
You might be interested in
Dakari makes 2 dozen jars of jam. The total weight of all of the filled jars is 211.2 ounces. When empty, each jar weighs 1.2 ou
Rzqust [24]

Answer:

Step-by-step explanation:

Total weight of all of the filled jars with jam = 211.2 ounces

When empty, each jar weighs 1.2 ounces

Total weight of 2 dozens of empty jar = 24 × 1.2 ounces

= 28.8 ounces

Total weight of jam in 2 dozens jar = Total weight of all of the filled jars with jam - Total weight of 2 dozens of empty jar

= 211.2 ounces - 28.8 ounces

= 182.4 ounces

The weight of jam in one jar = 182.4 ounces / 24 jars

= 7.6 ounces

The weight of jam in one jar = 7.6 ounces

3 0
2 years ago
Factor the algebraic expression below in terms of a single trigonometric function. csc 2x - 1
hjlf
(csc(x) + 1)(csc(x) -1)
5 0
2 years ago
Given that a 90% confidence interval for the mean height of all adult males in Idaho measured in inches was [62.532, 76.478]. Us
grigory [225]

Answer:

The confidence interval on this case is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)

For this case the confidence interval is given by (62.532, 76.478)[/tex]

And we can calculate the mean with this:

\bar X = \frac{62.532+76.478}{2}= 69.505

So then the mean for this case is 69.505

Step-by-step explanation:

Previous concepts

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

\bar X represent the sample mean  

\mu population mean (variable of interest)  

\sigma represent the population standard deviation  

n represent the sample size  

Assuming the X follows a normal distribution  

X \sim N(\mu, \sigma)

The confidence interval on this case is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)

For this case the confidence interval is given by (62.532, 76.478)[/tex]

And we can calculate the mean with this:

\bar X = \frac{62.532+76.478}{2}= 69.505

So then the mean for this case is 69.505

5 0
2 years ago
The average sea level in 1900 at London bridge was 33 feet. In 1990 it was 33.08 feet. Use linear interpolation or extrapolation
eduard

Answer:

In 1956, the height will be 33.05 ft

Step-by-step explanation:

Let +x+ = number of years after 1900

Calll 1900 +x+=+0+

Then 1990 is +x+=+90+

Let +y+ = height in feet

--------------------------

You are gven the points

( 0, 33 )

( 90, 33.08 )

Use general point-slope formula

+%28+y+-+33+%29+%2F+%28+x+-+0+%29+=+%28+33.08+-+33+%29+%2F+%28+90+-+0+%29+

Multiply both sides by +90x+

+90%2A%28+y+-+33+%29+=+.08x+

+90y+-+2970+=+.08x+

+90y+=+.08x+%2B+2970+

+y+=+.000889x+%2B+33+ ( equation to use )

--------------------------

Check:

does it go through ( 90, 33.08 ) ?

+33.08+=+.000889%2A90+%2B+33+

+33.08+=+.08001+%2B+33+

+33.08+=+33.08001+

close enough

-------------------------------

(a)

+x+=+61%0D%0A%7B%7B%7B+y+=+.000889x+%2B+33+

+y+=+.000889%2A61+%2B+33+

+y+=+.0542+%2B+33+

+y+=+33.0542+

In 1961, the height will be 33.05 ft

8 0
2 years ago
Lyn invested $7,000 into a investment paying 3% interest, compounded semi-annually, twice a year. After five years, how much wou
gayaneshka [121]

Answer:

Option B.) $8,123.79

Step-by-step explanation:

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

t=5\ years\\ P=\$7,000\\ r=0.03\\n=2  

substitute in the formula above  

A=\$7,000(1+\frac{0.03}{2})^{2*5}  

A=\$7,000(1.015)^{10}=\$8,123.79  

3 0
2 years ago
Other questions:
  • A math club is researching a golf tournament fund-raiser. It will cost $1,000 to host the tournament. If it rains, the club will
    8·2 answers
  • The answer plz I need the answer
    14·1 answer
  • The equation y=45x represents the number of miles, y, Mr. Miller’s car can travel using x gallons of gas. Which data display rep
    13·1 answer
  • Ally has 30 quaters. The ratio if her quarters to dimes is 2:3 and the ratio of her dimes to nickels is 5:3. How many nickles do
    13·1 answer
  • The mean number of students in a classroom at school a is 32.5 and there are 25 classrooms. The mean number of students at schoo
    11·1 answer
  • A student is raising money for cancer research. A local business agrees to donate an additional 25% of what the student raises,
    7·1 answer
  • Beth sold half of her comic books and then bought nine more. She now had 28. With how many did sh begin?
    15·2 answers
  • Classify each characteristic according to whether it is true for an amoeba, a clock, or both.
    8·2 answers
  • Sheila had a piece of rope that was 62.41 centimeters long. She cut pieces 8.95, 3.17, and39.77 centimeters long from the rope.
    5·1 answer
  • How much water must be added to 1 litre of 5% cordial mixture to produce a 4% cordial mixture?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!