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gulaghasi [49]
2 years ago
14

at the market , mS WINN BOUGHT 3/4 LB OF GRAPES AND 5/8 LB OF CHERRIES HOW MANY OUNCES OF GRAPES DID MS. WINN BUY

Mathematics
1 answer:
Svet_ta [14]2 years ago
7 0
16oz = 1lb so you can subtract 4 from 16 to get 12oz.
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An auto dealership sells minivans and sedans. In January, they sold 10
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After traveling for 4 hours and 1800 miles, an airplane begins a steady descent. When it begins descending, its altitude (height
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Answer:

Part 1)  Descending Rate = -2,000 ft/min

Part 2)  Starting altitude value is 33,000 ft

Part 3)  The linear equation for the plane's altitude (y) as a function of time (x) is:  y=-2000\,\frac{ft}{min} \,x\,+\,33000\,ft

Part 4)  The information not used for the equation is that the plane was travelling for 4 hours to cover 1800 miles before starting the descent

Step-by-step explanation:

Part 1)

The rate at which the airplane descends is given by the difference between final and initial altitude (17,000 ft-33,000 ft) divided the elapsed time (8 minutes):

Descending\,\,Rate\,= \frac{17000-33000}{8} \,\,\frac{ft}{min}=\frac{-16000}{8} \,\,\frac{ft}{min}=-\,2000\,\,\frac{ft}{min}

Part 2)

When graphing the descent (that is the plane's altitude as a function of time), the starting value for the altitude should be 33,000 ft

Part 3)

We can build the equation of the plane's altitude as a function of time in slope y-intercept form y = m x + b

by noticing that the slope "m" stands for the rate of descent that we found in part 1), and then using the information that at time zero (when the plane starts its descent), its altitude is 33000 ft:

y=m\,x\,+\,b\\y=-2000\,\frac{ft}{min} \,x\,+\,b\\33000=-2000\,\frac{ft}{min} \,(0)\,+\,b\\33000=b

with this information about the intercept "b", we can write the final expression for the plane's altitude as a function of time during its descent as:

y=-2000\,\frac{ft}{min} \,x\,+\,33000\,ft

Part 4)

The information that was not used to write the descent equation was the initial details about how long the plane traveled (4 hours) and for 1800 miles.

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2 years ago
The heights of adult women are approximately normally distributed about a mean of 65 inches with a standard deviation of 2 inche
FrozenT [24]
70 inches. The answer is e. 70 inches.
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