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yaroslaw [1]
2 years ago
11

Simplify 10/16 to lowest terms and find an equivalent fraction that has a denominator of 32?

Mathematics
1 answer:
goblinko [34]2 years ago
3 0

Answer:

The lowest fraction for \frac{10}{16} is \frac{5}{8} and a equivalent fraction with denominator of 32 is \frac{20}{32}.

Step-by-step explanation:

First, to have the fraction to the lowest terms we will have to divide the numerator and denominator by 2, this is:

\frac{10/2}{16/2}=\frac{5}{8}

As can be seen the expression couldn't be simplified more because there is no a common number that could divide the numerator and denominator.

Second, to have an equivalent fraction with 32 in the denominator we will have to multiply the denominator by 2 and of course the numerator, this is:

\frac{10*2}{16*2}=\frac{20}{32}

The lowest fraction for \frac{10}{16} is \frac{5}{8} and a equivalent fraction with denominator of 32 is \frac{20}{32}.

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A. 9 dozens
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The population of a town can be modeled by the regression equation y = 20,000(1.03x). Which is the best prediction for the popul
bixtya [17]

Answer:

The best prediction for the population in year 25 is 41,876\ people

Step-by-step explanation:

we have a exponential function of the form

y=a(b^{x})

where

a is the initial value

b is the base

In this problem

a=20,000\ people

b=1.03

b=1+r

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so

y=20,000(1.03^{x})

For x=25\ years

substitute

y=20,000(1.03^{25})

y=41,875.56\ people

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4 0
2 years ago
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Do oddsmakers believe that teams who play at home will have home field advantage? Specifically, do oddsmakers give higher point
vladimir2022 [97]

Answer:

Option 3 is correct.

The data do not provide sufficient evidence to reject H0; thus, we cannot conclude that the mean point spread of home games is higher than that of away games.

Step-by-step explanation:

Before anything else, we first give the null and alternative hypothesis for this question.

Null hypothesis would be that there isn't significant evidence to conclude that the mean point spread of home games is higher than that of away games.

H0: µ1 = µ2

And the alternative hypothesis would be that there is significant evidence to conclude that the mean point spread of home games is higher than that of away games.

Ha: μ1 > μ2

The data from the output of the analysis of the hypothesis test is missing from the question. It was obtained online and is attached to this solution of the question.

The table consists of the difference, the sample mean, the standard error of the mean, degree of freedom, the test statistic and most importantly, the p-value. It is the p-value that absolutely gives us the concluding statement of the hypothesis testing.

When the significance level for a test isn't provided, the convention is usually to use 5% significance.

Interpretation of p-value

When the (p-value > significance level), we fail to reject the null hypothesis and when the (p-value < significance level), we reject the null hypothesis and accept the alternative hypothesis.

So, for this question, significance level = 0.05

p-value = 0.4351

0.4351 > 0.05

Hence,

p-value > significance level

This means that we fail to reject the null hypothesis & say that 'The data do not provide sufficient evidence to reject H0; thus, we cannot conclude that the mean point spread of home games is higher than that of away games'.

Hope this Helps!!!

7 0
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Use the following compound interest formula to complete the problem.
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5 0
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Answer:

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