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fgiga [73]
2 years ago
3

Caleb performed an experiment in which he rolled a number cube 100 times. He recorded the results in a table.

Mathematics
2 answers:
balandron [24]2 years ago
7 0

Answer:

The experimental probability of rolling a 4 is 0.14.

Step-by-step explanation:

Given : Caleb performed an experiment in which he rolled a number cube 100 times. He recorded the results in a table.

Number Rolled - Frequency - Experimental Probability

1                                 15                    0.15

2                                17                     0.17

3                                17                     0.17

4                                14                      ?

5                                21                     0.21

6                                16                     0.16

To find : What was the experimental probability of rolling a 4?

Solution :

Formula to find the experimental probability is

\text{Experimental Probability}=\frac{\text{Frequency of the number}}{\text{Total number of times cube roll}}

We also notice that this pattern follows by other numbers also.

So, The experimental probability of rolling a 4 is

\text{Experimental Probability}=\frac{14}{100}

\text{Experimental Probability}=0.14

Therefore, The experimental probability of rolling a 4 is 0.14.

nydimaria [60]2 years ago
6 0
Answer: The experimental probability of rolling a 4 is 0.14

Experimental probability of rolling a 4 = (frequency of rolling a 4) / (Total number of rolling the number cube)

Frequency of rolling a 4 = 14
Total number of rolling the number cube = 100

Replacing in the formula above:
Experimental probability of rolling a 4 = 14 / 100
Experimental probability of rolling a 4 = 0.14 <span>
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Now imagine that instead of walking along the path 1→2→3→4→1, ann walks 80 meters on a straight line 33∘ north of east starting
stealth61 [152]

Answer:

Anna's walk  as a vector representation is 80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j} and refer attachment.

Step-by-step explanation:

Let the origin be the point 1 from where Ann start walking.

Ann walks 80 meters on a straight line 33° north of the east starting at point 1 as shown in figure below,

Resolving into the vectors, the vertical component will be 80Sin33° and Horizontal component will be 80Cos33° as shown in figure (2)

Ann walk as a vector representation is 80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}

Thus, Anna's walk  as a vector representation is 80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}

 




7 0
2 years ago
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Peter paid $79.80 for renting a tricycle for 6 hours. What was the rate per hour for renting the tricycle? (Input only numeric v
defon

Answer:

13.30

Step-by-step explanation:

$79.80 / 6 hours = $13.30

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2 years ago
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Assume that a fair die is rolled. The sample space is , 1, 2, 3, 4, 56, and all the outcomes are equally likely. Find P8. Expres
liraira [26]

Answer:

P\left(8\right)=0

Step-by-step explanation:

Assuming that a fair die is rolled.

  • The sample space is 1, 2, 3, 4, 5, 6 and all the outcomes are equally likely.

Let  X  be the set of all possible outcomes. Let  A  be an outcome.

So, the probability that  A  occurs is:

                                                        P\left(A\right)=\frac{|A|}{|X|}

As the set of all possible outcomes of the roll of a single die is:

X=\left\{1,2,3,4,5,6\right\}

Observe that

|X|=6

Here  

|A|=0   because 8 is not in the set sample space. So, the outcome of occurring the number 8 is not possible from the all possible outcomes.

So, the probability must be zero.

In other words,

                        P\left(A\right)=\frac{|A|}{|X|}

                         P\left(8\right)=\frac{0}{6}=0

Therefore,

                   P\left(8\right)=0

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2 years ago
Lilly and Alex went to a Mexican restaurant. Lilly paid $9 for 2 tacos and 3 enchiladas, and Alex paid $12.50 for 3 tacos and 4
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Let's call Tacos t and Enchiladas e. 
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Alex paid $12.50 for 3t and 4e.
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2t + 3e = 9.00
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Lucia is making a 21.6 centimeter beaded string to hang in the window. She decides to put a green bead every 0.4 centimeters and
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21.6 ÷ 0.4 = 54 times for green
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Together, 90 beads. Separately, 54 green and 36 purple.
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