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IgorC [24]
2 years ago
5

A scale drawing of a house addition shows a scale factor of 1 in. = 3.3 ft. Josh decides to make the house addition smaller, and

he changes the scale of the drawing to 1 in. = 1.1 ft. What is the change in the scale factor from the old scale to the new scale? Help Please!!
Mathematics
2 answers:
emmasim [6.3K]2 years ago
7 0
It is decreased by a factor of 3. You can determine this by realizing that one inch original equals 3.3 feet, but the equals 1.1 feet, and 3.3/1.1 = 3.
trasher [3.6K]2 years ago
6 0

Answer:

<h2>it is 3</h2>

Step-by-step explanation:

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Darya [45]

Answer: if you simplify the equation, your answer should be 16

Step-by-step explanation: Simplify  2+22+22+2  to  444.

8÷2×48\div 2\times 48÷2×4

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Simplify  8÷28\div 28÷2  to  444.

4×44\times 44×4

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Simplify.

16

4 0
2 years ago
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Of the28 golf balls 5/7 are white how many are white
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20 balls are white

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5/7* 28

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2 years ago
Deana gave her younger sister $5.48 to buy some candy. Her sister returned $2.84 in change. How much did her sister spend on can
alexandr402 [8]

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$2.64

Step-by-step explanation:Get rid of the dollar sign and just subtract like normal.

 

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                                - 2.84

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The dolphins at the sea aquarium are fed 2 1/3 buckets of fish each day. The walruses are fed 5 times as much fish as the dolphi
bezimeni [28]

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2 years ago
A basketball player is shooting a basketball toward the net. The height, in feet, of the ball t seconds after the shot is modele
tresset_1 [31]

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Yes, between 0.84 seconds and 0.85 seconds after the shot is launched.

Step-by-step explanation:

\text{The equation for ball height} : 6+30\cdot t-16\cdot t^{2}\\\text{The equation for shot blocker's height} : 9+25\cdot t-16\cdot t^{2}

But, the shot is made before two tenths of a second or 0.2 seconds therefore modified equation for ball height is :

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Now for the shot to be blocked,the height of shot blocker must be greater than the height of the ball which is shot before 0.2 seconds :

\implies 9+25\cdot t-16\cdot t^{2}\geq 6+30\cdot (t-0.2)-16\cdot (t-0.2)^{2}\\\implies 9+25\cdot t-16\cdot t^{2}\geq 6+30\cdot t-6-16\cdot (t^{2}-0.4\cdot t+0.04)\\\implies9+25\cdot t-16\cdot t^{2}\geq 30\cdot t-16\cdot t^{2}+6.4\cdot t-0.64\\\implies 9+25\cdot t\geq 36.4\cdot t-0.64\\\implies 9.64\geq 11.4\cdot t\\\\\implies t\leq \frac{9.64}{11.4}\approx 0.846

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7 0
2 years ago
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