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IgorC [24]
1 year ago
5

A scale drawing of a house addition shows a scale factor of 1 in. = 3.3 ft. Josh decides to make the house addition smaller, and

he changes the scale of the drawing to 1 in. = 1.1 ft. What is the change in the scale factor from the old scale to the new scale? Help Please!!
Mathematics
2 answers:
emmasim [6.3K]1 year ago
7 0
It is decreased by a factor of 3. You can determine this by realizing that one inch original equals 3.3 feet, but the equals 1.1 feet, and 3.3/1.1 = 3.
trasher [3.6K]1 year ago
6 0

Answer:

<h2>it is 3</h2>

Step-by-step explanation:

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Sales tax on an item is directly proportional to the cost of the item purchased. If the tax on a $600 item is $42, what is the s
Dafna11 [192]
Answer: $65.10

Step-by-step work:

1.Set the ratio
\frac{600}{42}  =  \frac{930}{x}
2.Cross-multiply
600x = 930(42)
600x = 39060
3.Divide to single out x
600x \div 600 = 39060 \div 600
x = 65.10


4 0
2 years ago
The 40th term of the number sequence is 119.<br> (b) Work out the 41st term of the number sequence.
dolphi86 [110]
100000fjwjsnfbc kdjdbf
7 0
1 year ago
A group of friends are going ice skating. The price of admission is $3.25. As a group, they spent $14 on refreshments. If they s
Helen [10]
Start with $30.25. 
Subtract $14.00 to isolate the amount of money spent on admission. 
30.25-14.00= 16.25. As a group $16.25 was spent on admission.
Admission is 3.25 per person. Divide 16.25 by 3.25. 
16.25/3.25=5. 
5 friends went ice skating. 
4 0
2 years ago
Read 2 more answers
Ray CE is the angle bisector of ACD. Which statement about the figure must be true? mECD = mECB mACE = mACD ACE DCB
Ainat [17]

Answer:

ACE = ECD is the answer

Step-by-step explanation:

5 0
2 years ago
A boat sails on a bearing of 038°anf then 5km on a bearing of 067°.
I am Lyosha [343]

This question is not complete

Complete Question

A boat sails 4km on a bearing of 038 degree and then 5km on a bearing of 067 degree.(a)how far is the boat from its starting point.(b) calculate the bearing of the boat from its starting point

Answer:

a)8.717km

b) 54.146°

Step-by-step explanation:

(a)how far is the boat from its starting point.

We solve this question using resultant vectors

= (Rcos θ, Rsinθ + Rcos θ, Rsinθ)

Where

Rcos θ = x

Rsinθ = y

= (4cos38,4sin38) + (5cos67,5sin67)

= (3.152, 2.4626) + (1.9536, 4.6025)

= (5.1056, 7.065)

x = 5.1056

y = 7.065

Distance = √x² + y²

= √(5.1056²+ 7.065²)

= √75.98137636

= √8.7167296826

Approximately = 8.717 km

Therefore, the boat is 8.717km its starting point.

(b)calculate the bearing of the boat from its starting point.

The bearing of the boat is calculated using

tan θ = y/x

tan θ = 7.065/5.1056

θ = arc tan (7.065/5.1056)

= 54.145828196°

θ ≈ 54.146°

7 0
1 year ago
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