Answer:
y = 12x + 9 is the answer.
Step-by-step explanation:
Since the given equation is 2x + 12 y = -1
12y = -2x -1


Now this line is in the form of y = mx + c
Here m = slope = -1/12
We have to calculate the slope of another line perpendicular to this line and passing through (0, 9).
Let the equation is y = m' + c'
We know m×m' = -1 for two perpendicular lines

m' = 12
Therefore the equation will be
y = 12x + c'
Since this line passes through ( 0, 9)
9 = 12×0 + c'
c' = 9
Now the equation will be
y = 12x + 9
This is the answer.
Answer:
Hey the answer is e i think
Step-by-step explanation:
Answer: The lower bound of confidence interval would be 0.116.
Step-by-step explanation:
Since we have given that
p = 13.2%= 0.132
n = 1105
At 90% confidence,
z = 1.645
So, Margin of error would be

So, the lower bound of the confidence interval would be

Hence, the lower bound of confidence interval would be 0.116.
The value remains under the radical is 8 ⇒ last answer
Step-by-step explanation:
Let us revise how to write the exponent as a radical
can be written as ![\sqrt[n]{a^{m}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5E%7Bm%7D%7D)
- To simplify the radical factorize the base "a" to its prime factors
Example:
, - Factorize 54 into prime factors ⇒ 54 = 2 × 3 × 3 × 3 =

![\sqrt[3]{(54)^{2}}=\sqrt[3]{[2(3^{3}]^{2}}=\sqrt[3]{2^{2}*3^{6}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%2854%29%5E%7B2%7D%7D%3D%5Csqrt%5B3%5D%7B%5B2%283%5E%7B3%7D%5D%5E%7B2%7D%7D%3D%5Csqrt%5B3%5D%7B2%5E%7B2%7D%2A3%5E%7B6%7D%7D)
- 2² can not go out the radical because 2 is less than 3 not divisible by 3
can go out the radical because 6 is divisible by 3, then divide 6 by 3, so it will be 3² out the radical![\sqrt[3]{(54)^{2}}=3^{2}\sqrt[3]{2^{2}}=9\sqrt[3]{4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%2854%29%5E%7B2%7D%7D%3D3%5E%7B2%7D%5Csqrt%5B3%5D%7B2%5E%7B2%7D%7D%3D9%5Csqrt%5B3%5D%7B4%7D)
Now let us solve your problem
∵ ![1250^{\frac{3}{4}}=\sqrt[4]{1250^{3}}](https://tex.z-dn.net/?f=1250%5E%7B%5Cfrac%7B3%7D%7B4%7D%7D%3D%5Csqrt%5B4%5D%7B1250%5E%7B3%7D%7D)
- Factorize 1250 to its prime factors
∵ 1250 = 2 × 5 × 5 × 5 × 5
∴ 
∴ ![\sqrt[4]{(2*5^{4})^{3}}=\sqrt[4]{2^{3}*5^{12}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%282%2A5%5E%7B4%7D%29%5E%7B3%7D%7D%3D%5Csqrt%5B4%5D%7B2%5E%7B3%7D%2A5%5E%7B12%7D%7D)
∵ 2³ can not go out the radical because 3 < 4 and not divisible by it
-
can go out the radical because 12 can divided by 4
∵ 12 ÷ 4 = 3
∴
can go out the radical as 5³
∴ ![\sqrt[4]{1250}=5^{3}\sqrt[4]{2^{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B1250%7D%3D5%5E%7B3%7D%5Csqrt%5B4%5D%7B2%5E%7B3%7D%7D)
∴ ![\sqrt[4]{1250}=125\sqrt[4]{8}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B1250%7D%3D125%5Csqrt%5B4%5D%7B8%7D)
∴ The value remains under the radical = 8
The value remains under the radical is 8
Learn more:
You can learn more about the radicals in brainly.com/question/7153188
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