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nlexa [21]
2 years ago
11

What is the value of x in the figure below? In this diagram, ΔABD ~ ΔCAD

Mathematics
2 answers:
tangare [24]2 years ago
8 0
X/10 = 10 / 16
16x = 100
    x = 100/16
    x = 25/4

answer is F. 25/4

n200080 [17]2 years ago
4 0
ANSWER ON APEX IS 25/4.
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What is the value of k such that x-5 is a factor of x3 – x2 + kx - 30?
Paraphin [41]

Answer:

k = - 14

Step-by-step explanation:

given that (x - 5) is a factor of the polynomial then x = 5 is a root and

x³ - x² + kx - 30 = 0 for x = 5, that is

5³ - 5² + 5k - 30 = 0

125 - 25 + 5k - 30 = 0

70 + 5k = 0 ( subtract 70 from both sides )

5k = - 70 ( divide both sides by 5 )

k = - 14


5 0
2 years ago
Some of the steps in the derivation of the quadratic formula are shown. Step 3: –c + StartFraction b squared Over 4 a EndFractio
icang [17]

Answer:

The square root of terms separated by addition and subtraction cannot be calculated individually.

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
The pH scale measures how acidic or basic a substance is. Lemon juice is said to have a pH of less than 4 and greater than 1.5.
castortr0y [4]

Let's say x is J because it's Lemon Juice.

It's said that the pH of J is less than 4 so: pH(J) < 4 and pH(J) is greater than 1.5 so: pH(J) > 1.5

Now we can construct:

1.5 < pH(J) \wedge pH(J) < 4

Or simply:

1.5 < pH(J) < 4

We can also write this with an interval:

pH(J)\in(1.5, 4)

Hope this helps.

r3t40

8 0
2 years ago
What is the answer to the problem 44.84 x 9.84?
Marta_Voda [28]
I hope this helps you

7 0
2 years ago
How many solutions does the equation sin(5x) = 1/2 have on the interval (0, 2PI]
Darina [25.2K]

Answer:

Step-by-step explanation:

Given the equation

Sin(5x) = ½

5x = arcSin(½)

5x = 30°

Then,

The general formula for sin is

5θ = n180 + (-1)ⁿθ

Divide through by 5

θ = n•36 + (-1)ⁿ30/5

θ = 36n + (-1)ⁿ6

The range of the solution is

0<θ<2π I.e 0<θ<360

First solution

When n = 0

θ = 36n + (-1)ⁿθ

θ = 0×36 + (-1)^0×6

θ = 6°

When n = 1

θ = 36n + (-1)ⁿ6

θ = 36-6

θ = 30°

When n = 2

θ = 36n + (-1)ⁿ6

θ = 36×2 + 6

θ = 78°

When n =3

θ = 36n + (-1)ⁿ6

θ = 36×3 - 6

θ = 102°

When n=4

θ = 36n + (-1)ⁿ6

θ = 36×4 + 6

θ = 150

When n =5

θ = 36n + (-1)ⁿ6

θ = 36×5 - 6

θ = 174°

When n = 6

θ = 36n+ (-1)ⁿ6

θ = 36×6 + 6

θ = 222°

When n = 7

θ = 36n + (-1)ⁿ6

θ = 36×7 - 6

θ = 246°

When n =8

θ = 36n + (-1)ⁿ6

θ = 36×8 + 6

θ = 294°

When n =9

θ = 36n + (-1)ⁿ6

θ = 36×9 - 6

θ = 318°

When n =10

θ = 36n + (-1)ⁿ6

θ = 36×10 + 6

θ = 366°

When n = 10 is out of range of θ

Then, the solution is from n =0 to n=9

So the equation have 10 solutions in the range 0<θ<2π

4 0
2 years ago
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