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2 years ago

4

What is the equation of the midline for the function y = 2sin(x - π) + 3

2 answers:

Greeley [361]2 years ago

7 0

The vertical shift of the graph moves the function up three units. Since there are no other major shifts to the height of the graph, the midline has an equation of y = 3.

Lera25 [3.4K]2 years ago

5 0

The maximum value of sin(x-π) is 1, the minimum is -1, so the maximum value for the function <span>y = 2sin(x - π) + 3 is 2*1+3=5, the minimum is -2+3=1, half way between 5 and 1 is 3, so y=3 is the midline. </span>

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Which equation represents a line that passes through (–2, 4) and has a slope of 2/5? y – 4 = 2/5 (x 2) y 4 = 2/5 (x – 2) y 2 = 1

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2 years ago

Below is the five Number summary for a 136 hikers who recently completed the John muir trail JMT the variable is the amount of t

Helga [31]

Answer:

$IQR = Q_3 -Q_1 = 28-18 = 10$

Now we can find the limits in order to determine outliers like this:

$Left = Q_1 -1.5 IQR = 18 -1.5*10=3$

$Right = Q_1 +1.5 IQR = 18 +1.5*10=33$

So for this case the left boundary would be 3, if a value is lower than 3 we consider this observation as an outlier

b. 3

Step-by-step explanation:

For this case we have the following summary:

$Minimum = 9$ represent the minimum value

$Q_1 = 18$ represent the first quartile

$Median =Q_2= 21$ represent the median

$Q_3 = 28$ represent the third quartil

$Maximum=56$ represent the maximum

If we use the 1.5 IQR we need to find first the interquartile range defined as:

$IQR = Q_3 -Q_1 = 28-18 = 10$

Now we can find the limits in order to determine outliers like this:

$Left = Q_1 -1.5 IQR = 18 -1.5*10=3$

$Right = Q_1 +1.5 IQR = 18 +1.5*10=33$

So for this case the left boundary would be 3, if a value is lower than 3 we consider this observation as an outlier

b. 3

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2 years ago