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Bas_tet [7]
2 years ago
15

Calculate the wavelength associated with a 20Ne+ ion moving at a velocity of 2.0 × 105 m/s. The atomic mass of Ne-20 is 19.992 a

mu.
Chemistry
2 answers:
Vadim26 [7]2 years ago
6 0
Λ = h/p = h/mv; where λ is the wavelength in meters, h is the Planck's constant = 6.6261 × 10^-31 J/s, m is the mass (in kg) and v is the velocity in m/s.
velocity = 2.0 × 10^5 m/s
1 amu = 1.66 × 10^-24 g
Therefore; 19.992 amu will have = 1.66 ×19.992 ×10^-24g
 = 3.319 × 10^-23 g
Thus; λ= (6.6261 ×10^-31)/(3.319×10^-23)×2×10^5)
     = 1.0 × 10^-13 m
worty [1.4K]2 years ago
5 0

1 atomic mass unit is equal to 1.6605 × 10⁻²⁷Kg

Mass, m = 19.992 amu = 19.992 × 1.6605 × 10⁻²⁷

= 3.321 × 10⁻²⁶Kg

Speed, v = 2.0 × 10⁵ m/s

De Brogile equation:

Wavelength = h/mv

= 6.626 × 10³⁴ / (3.321 × 10⁻²⁶ × 2.0 × 10⁵)

= 9.976 × 10⁻¹⁴ m = 0.9976 × 10⁻¹³ m = 1.0 × 10⁻¹³ m

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The net ionic equation of borax hydrolysis would be:

 <span>Na2B4O7 + 7H2O-----------------> 2 NaOH + 4 H3BO3
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Wherein 2 moles of sodium hydroxide and 4 moles of boric acid are produced by the hydrolysis.
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2 years ago
1. How many atoms of nitrogen are there in 0.50 mol of (NH4)2CO3?
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Answer:

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An atom of lithium-7 has an equal number of
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What alkene reacts the fastest with HBr?
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The first step in the reaction is the double bond of the Alkene going after the H of HBr. This protonates the Alkene via Markovnikov's rule, and forms a carbocation. The stability of this carbocation dictates the rate of the reaction. 

<span>So to solve your problem, protonate all your Alkenes following Markovnikov's rule, and then compare the relative stability of your resulting carbocations. Tertiary is more stable than secondary, so an Alkene that produces a tertiary carbocation reacts faster than an Alkene that produces a secondary carbocation.


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3 0
2 years ago
Read 2 more answers
The concentration of sodium chloride in an aqueous solution that is 2.23 M and that has a density of 1.01 g/mL is __________% by
amm1812

Answer:

The concentration of sodium chloride in an aqueous solution that is 2.23 M and that has a density of 1.01 g/mL is 12.90% by mass

Explanation:

2.23 M aqueous solution of NaCl means there are 2.23 moles of NaCl in 1000 mL of solution.

We know that density is equal to ratio of mass to volume.

Here density of solution is 1.01 g/mL.

So mass of 1000 mL solution = (1.01\times 1000) g = 1010 g

molar mass of NaCl = 58.44 g/mol

So mass of 2.23 moles of NaCl = (2.23\times 58.44) g = 130.3 g

% by mass  is ratio of mass of solute to mass of solution and then  multiplied by 100.

Here solute is NaCl.

So % by mass of 2.23 M aqueous solution of NaCl = \frac{130.0}{1010}\times 100% = 12.90%

3 0
2 years ago
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