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igomit [66]
2 years ago
3

In isosceles trapezoid WKMN, WN=6, WK=9, and the perimeter of WKMN is 40. What is the length of KM?

Mathematics
1 answer:
Dmitry_Shevchenko [17]2 years ago
7 0
Answer: The length of KM is 16.

In an isosceles trapezoid, the two non-parallel sides are congruent. Therefore, we have two options: either there are two 9's or two 6's in the trapezoid.

Let's try both options to find the length of the missing side:

40 - 9 - 6 - 6 = 19

OR 

40 - 6 - 9 - 9 = 16

The only choice that is an option is 16.
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Explain how rays AB and AC form both a line and an angle.
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So you have a line that is both a line and an angle with A in the middle.

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A sapling, or young tree, is planted in a garden. After 3 years, it is 180 cm tall. After 7 years, it is 368 cm tall. How tall w
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2 years ago
A high percentage of people who fracture or dislocate a bone see a doctor for that condition. Suppose the percentage is 99%. Con
marishachu [46]

Answer:

(i) 0.15708

(ii) 0.432488

(iii) 3

Step-by-step explanation:

Given that, 99% of people who fracture or dislocate a bone see a doctor for that condition.

There is only two chance either the person having fracture or dislocation of bone will either see the doctor or not.

As per previous data, if one person got a fracture or dislocation of bone, the chance of seeing the doctor is 0.99. Assuming this chance is the same for every individual, so the total number of people having fractured or dislocated a bone can be considered as Bernoulli's population.

Let p be the probability of success represented by the chances of not seeing a doctor by any one individual having fractured or dislocated a bone.

So, p=1-0.99=0.01

According to Bernoulli's theorem, the probability of exactly r success among the total of n randomly selected from Bernoulli's population is

P(r)=\binom{n}{r}p^r(1-p)^{n-r}\cdots(i)

(i) The total number of persons randomly selected, n=400.

The probability that exactly 5 of them did not see a doctor

So, r=5 , p=0.01

Using equation (i),

P(r=5)=\binom{400}{5}(0.01)^5(1-0.01)^{400-5}

=\frac{400!}{(400-5)!\times 5!}(0.01)^5(0.99)^{395}

=0.15708

(ii) The probability that fewer than four of them did not see a doctor

=P(r

=P(r=0)+P(r=1)+P(r=2)+P(r=3)

=\binom{400}{0}(0.01)^0(0.99)^{400}+\binom{400}{1}(0.01)^1(0.99)^{399}+\binom{400}{2}(0.01)^2(0.99)^{398}+\binom{400}{3}(0.01)^3(0.99)^{397}

=0.017951+0.072527+0.146154+0.195856

=0.432488

(iii) The expected number of people who would not see a doctor

=np

=300\times 0.01

=3

7 0
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Zach uses his car for business and must keep accurate driving records so that his company will reimburse him for car expenses. W
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His end mileage minus his starting mileage will give us the total number of miles he traveled.  28017-26645=1372 miles traveled.
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2 years ago
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