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2 years ago

The equation below shows the relationship between the temperature in degrees Celsius, C, and degrees Fahrenheit, F:

Mathematics

2 answers:

algol [13]2 years ago

5 0

Th first answer
F = 9 over 5 C + 32

aliya0001 [1]2 years ago

5 0

Answer:

Option 1 - F = 9 over 5C + 32

Step-by-step explanation:

Given : The equation below shows the relationship between the temperature in degrees Celsius, C, and degrees Fahrenheit, F:

C = 5 over 9(F − 32)

To find : Which of the following formulas correctly solves for F?

Solution :

We can write the equation as

$C=\frac{5}{9}(F-32)$

Now, we solve for F,

Multiply both side by 9,

$9C=5(F-32)$

Open the brackets,

$9C=5F-160$

$9C+160=5F$

Divide both side by 5,

$\frac{9C+160}{5}=F$

Solve,

$\frac{9}{5}C+32=F$

So, The value of F is F=9 over 5C +32.

Therefore, Option 1 is correct.

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On a coordinate plane, a triangle has points (negative 5, 1), (2, 1), (2, negative 1).

daser333 [38]

Answer:

Step-by-step explanation:

Given a triangle has points:

(-5,1),(2,1), (2,-1)

Let us label the points:

A(2,1),

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To find:

Distance between (−5, 1) and (2, −1) i.e. BC.

Horizontal leg AB and

Vertical leg, AC.

Solution:

Please refer to the attached diagram for the labeling of the points on xy coordinate plane.

We can simply use Distance formula here, to find the distance between two coordinates.

Distance formula :

$D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

For BC:

$x_2 = 2\\x_1 = -5\\y_2 = -1\\y_1 = 1$

$BC = \sqrt{(2--5)^2+(-1-1)^2} = \sqrt{63}$

Horizontal leg, AC:

$x_2 = -5\\x_1 = 2\\y_2 = 1\\y_1 = 1$

$AC = \sqrt{(2-(-5))^2+(1-1)^2} = 7$

Vertical Leg, AB:

$x_2 = 2\\x_1 = 2\\y_2 = -1\\y_1 = 1$

$AB = \sqrt{(2-2)^2+(-1-1)^2} = 2$

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Usimov [2.4K]

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2 years ago

In the trapezoid ABCD ( AB ∥ CD ) point M∈ AD , so that AM:MD=3:5. Line l ∥ AB and going trough point M intersects diagonal AC a

geniusboy [140]

Answer:

BC:BN=8:3

Step-by-step explanation:

ABCD is a trapezoid and there is a point m which belongs to AD such that AM:MD=3:5.Line "l" parallel to AB intersects the diagonal AC at p and BD at N.

Now, we know that the parallel lines divide the transversal into the segments with equal ratio, therefore, BN:NC=AM:MD

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