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notsponge [240]
1 year ago
13

What substitution should be used to rewrite 6(x + 5)2 + 5(x + 5) – 4 = 0 as a quadratic equation? u = (x + 5) u = (x – 5) u = (x

+ 5)2 u = (x – 5)2
Mathematics
1 answer:
Pachacha [2.7K]1 year ago
5 0
6(x+5)² + 5(x+5)-4 = 0

(x+5)(x+5) = x(x+5)+5(x+5) = x² + 5x + 5x + 25 = x² + 10x + 25

6(x²+10x+25) + 5(x+5) - 4 = 0
6x² + 60x + 150 + 5x + 25 - 4 = 0
6x² + 60x + 5x + 150 + 25 - 4 = 0
6x² + 65x + 171 = 0

<span>u = (x + 5)</span>
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Lincoln Middle School has a total of $200 to spend on notebooks and tablets for the school board meeting. Notebooks cost $7 each
Anton [14]
The school can buy fifteen notebooks and nineteen tablets.  15X7=105 and 5X19=95.  95+105=200.  The first thing you want to do is realize that 5Xanything will give you an answer that has a 0 or a five at the end, so you want to find a product by 7 that ends with a 0 or 5 too.
4 0
2 years ago
Sometimes a dilation is an enlargement, and sometimes it is a reduction. Explain what types of numbers for scale factors causes
vovikov84 [41]
If your scale factor has absolute value greater than 1, the dilation is an enlargement. 
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<span>If the scale factor is equal to 1, the image is congruent to the preimage. </span>
3 0
2 years ago
Read 2 more answers
The equation y=−0.0088x2+0.79x+15 models the speed x (in miles per hour) and average gas mileage y (in miles per gallon) for a v
rewona [7]
Answer: 30.72 miles per gallon

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</span><span> y=−0.0088x2+0.79x+15
y= -31.68 +47.4 + 15
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5 0
2 years ago
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I need to find both of the solutions to the equation 100+(n-2)^ = 149
rodikova [14]

Answer:

Step-by-step explanation:

hello :

100+(n-2)² = 149

100-100+(n-2)² = 149-100

(n-2)² = 49  

(n-2)² - 49  =0    but 49=7²

(n-2)² - 7²  =0   use identity : a²-b²=(a-b)(a+b)

(n-2-7)(n-2+7)=0

(n-9)(n+5)=0

n-9=0 or n+5=0

n=9 or n=-5

                                             

5 0
2 years ago
A company administers an "aptitude test for managers" to aid in selecting new management trainees. Prior experience suggests tha
RoseWind [281]

Answer:

0.94

Step-by-step explanation:

The question after this basically is:

<em>"If the applicant passes the "aptitude test for managers", what is the probability that the applicant will succeed in the management position?"</em>

<em />

So,

P(successful if hired) = 60% = 0.6 [let it be P(x)]

P(success at passing the test) = 85% = 0.85   [let it be P(y)]

P(successful and pass the test) =  P(x) + P(y) -[P(x)*P(y)]

So,

P(successful and pass the test) = 0.6 + 0.85 - (0.6*0.85) = 0.94 (94%)

5 0
1 year ago
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