The equation is already balanced so the mole ratio is just 1/1 and from the question you could conclude that the equation is a single displacement
Draw the products of the complete hydrolysis of a ketal. draw all products of the reaction.
2 answers:
Following reaction shows the complete hydrolysis of ketal. The products formed are 1) Diol and 2) Ketone. Mechanism is shown below,
Answer:
The main products obtained from complete hydrolysis of a ketal are ketone (90%) and hydrate (10%), we also obtained as byproducts two alcohols (ROH and R
OH). See attached image
Explanation:
To understand this question, one has to know what a ketal is and also what is complete hydrolysis.
Ketal: functional group present in organic chemistry that has a central carbon attached to 2 R groups and 2 OR.
Hydrolysis: reaction of water with a molecule
We can observe in the diagram that this reaction is found in equilibrium, meaning that depending on the concentration of the diverse substrates and products, the reaction will favor the direction towards one or the other.
Note: In the last part of the reaction we can observe that the equilibrium favors the production of ketone over that of a hydrate. This occurs since a ketone is more stable than that of a hydrate (about 90% will be ketone while 10% will be a hydrate).
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Answer:
Ethynylcyclopropane is the stable isomer for given alkyne.
Explanation:
In order to solve this problem we will first calculate the number of Hydrogen atoms. The general formula for alkynes is as,
CₙH₂ₙ₋₂
Putting value on n = 5,
C₅H₂.₅₋₂
C₅H₈
Also, the statement states that the compound contains one ring therefore, we will subtract 2 hydrogen atoms from the above formula i.e.
C₅H₈ ------------(-2 H) ----------> C₅H₆
Hence, the molecular formula for given compound is C₅H₆
Below, 4 different isomers with molecular formula C₅H₆ are attached.
The first compound i.e. ethynylcyclopropane is stable. As we know that alkynes are sp hybridized. The angle between C-C-H in alkynes is 180°. Hence, in this structure it can be seen that the alkyne part is linear and also the cyclopropane part is a well known moiety.
Compounds 3-ethylcycloprop-1-yne, <u>cyclopentyne </u>and 3-methylcyclobut-1-yne are highly unstable. The main reason for the instability is the presence of triple bond in three, five and four membered ring. As the alkynes are linear but the C-C-H bond in these compound is less than 180° which will make them highly unstable.
