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levacccp [35]
2 years ago
14

An 8.50 L tire contains 0.552 mol of gas at a temperature of 305 K. What is the pressure (in atm and in psi) of the gas in the t

ire? (1 atm is approximately equal to 14.7 psi.) Express the pressures in atmospheres and pounds per square inch to three significant figures separated by a comma.
Chemistry
2 answers:
yuradex [85]2 years ago
8 0

Answer:

pV=nRT; p=nRT/V

p=0.552Mol*8.314J/MolᵒK*305K/0.0085m³=164675.887Pa

p=1.625atm

1.625atm*14.7psi/1atm=23.888psi

Anestetic [448]2 years ago
6 0

Answer:

pressure = 1.625 atm or 23.89 psi

Explanation:

Step 1: Data given

Volume = 8.50 L

Number of moles of gas

Temperature = 305 K

Step 2: Calculate pressure

p*V = n*R*T

⇒with p = the pressure of the gas = TO BE DETERMINED

⇒with V= the volume of the gas = 8.50 L

⇒with n = the number of moles of gas = 0.552 moles

⇒with R = the gas constant = 0.08206 L*atm/mol*K

⇒with T = the temperature = 305 K

p = (n*R*T)/V

p = (0.552*0.08206*305)/8.50

p = 1.625 atm

1.625 * 14.7 = 23.89

1.625 atm = 23.89 psi

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