Question

Given the graph below, find WV.

Answer 1

Answer:

$WV=\sqrt{40}\approx 6.32$

Step-by-step explanation:

We have been given a graph of coordinate plane. We are asked to find the length of segment WV.

Point W(-2,-2) and point V(0,4).

We will use distance formula to solve our given problem.

$\text{Distance}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$\text{Distance}=\sqrt{((0-(-2))^2+4-(-2))^2}$

$\text{Distance}=\sqrt{(+2)^2+(4+2)^2}$

$\text{Distance}=\sqrt{2^2+6^2}$

$\text{Distance}=\sqrt{4+36}$

$\text{Distance}=\sqrt{40}$

$\text{Distance}=6.324555$

$\text{Distance}\approx 6.32$

Therefore, the length of segment WV is approximately 6.32 units.

Answer 2

According to the a^2+b^2=c^2  c= square root of(2^2+6^2)=sqrt{40}or2 sqrt{10} approximately 6.325. Hope this thanks.