The probability of the pointer lands on red(R) both spin = 
Step-by-step explanation:
Given,
The number of parts = 6
The pointer is spun twice.
To find the probability of the pointer lands on red(R) both spin.
Formula
Probability of an event = number of required outcomes ÷ the total number of outcomes.
P(A and B) = P(A)×P(B)
Now,
For one spin,
A = RED comes.
For second spin,
B = RED comes
So,
P(A) = 
and P(B) =
Then,
P(A and B) = × =
Hence, the probability of the pointer lands on red(R) both spin =
<span>There are two possible ways where you can express this. First, is by presenting the equation net of 5 percent which is "x=1.0355n+2.6505m". The other way to express such is by presenting it with gross amount which is "x= (1-0.05)(1.09n+2.79m)"
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A margin of error means how much a prediction can be wrong. So if a prediction is 54% and the margin of error is 4%, then it can be wrong by 4 percent, so it could be 4 % less (50%) or more (58%).
Correct Answer;
X is the actual answer.
50%≤x≥58%
brainliest pls
Hello there!
the answer would be A
Hope this helps! :)
~Zain
Fred has 1384.5
Hope this helps, please dont kill me if im wrong
